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Pachacha [2.7K]
3 years ago
10

in circle O the radius is 4ft and the measure of minor arc ab is 120 degrees find the length of minor arc ab to the nearest inte

ger
Mathematics
1 answer:
KIM [24]3 years ago
4 0

Answer:

8\:\text{ft}

Step-by-step explanation:

The length of the arc is proportional to the degree measure it in encompasses. Since there are 360 degrees in a circle and the arc is 120 degrees, the arc's length will be \frac{120}{360}=\frac{1}{3} of the circle's length (circumference).

The circumference of a circle is given by 2\pi r, where r is the radius of the circle. Therefore, the circumference of the circle is 2\pi(4)=8\pi. As we found earlier, the length of the arc is \frac{1}{3} of this circumference. Therefore, the arc's length is 8\pi\cdot \frac{1}{3}=\frac{8\pi}{3}.

To the nearest integer, this is \approx \boxed{8\:\text{ft}}.

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A helicopter flying 3590 feet above ground spots the top of a 150-foot y'all cell phone tower at an angle of depression of 77° h
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Step-by-step explanation:

Please find the attachment.

Let x be the distance helicopter needs to fly to be directly over the tower.

We have been given that a helicopter flying 3590 feet above ground spots the top of a 150-foot y'all cell phone tower at an angle of depression of 77°.

We can see from our attachment that helicopter, tower and angle of depression forms a right triangle.

As height of tower is 150 feet, so the vertical distance between helicopter and tower will be 3590-150=3440 feet.

We cab see from our attachment that the side with length 3590-150 feet is opposite and side x is adjacent side to 77 degree angle.

Since we know that tangent relates the opposite side of a right triangle to its adjacent side, so we will use tangent to find the length of x.

\text{Tan}=\frac{\text{Opposite}}{\text{Adjacent}}

Upon substituting our given values in above formula we will get,

\text{Tan}(77^o)=\frac{3590-150}{x}

\text{Tan}(77^o)=\frac{3440}{x}

x=\frac{3440}{\text{Tan}(77^o)}

x=\frac{3440}{4.331475874284}  

x=794.1865\approx 794.19

Therefore, the helicopter must fly approximately 794.19 feet to be directly over the tower.

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97.965—97.97—98

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