Question

How do I solve 3= log8+3log x?

Answer 1

3 = log(8) + log(x³) 

When adding logs, you are multiplying the terms altogether. 

3 = log(8x³) 

Then, by log_a b = n ==> aⁿ = b: 

10³ = 8x³ [Since the base is not given, I assume that the base is 10] 
1000 = 8x³ 

Finally, solve for x. 

1000/8 = x³ 
x³ = 125 
x = (125)^(1/3) . . .Set both sides to the power of 1/3. 
x = 5 

Hence, x = 5.