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Vanyuwa [196]
3 years ago
15

Help me out now Please I'm stuck on this

Mathematics
1 answer:
Elena-2011 [213]3 years ago
8 0

5x + 2(x + 1) ≤ 23

Distribute the 2.

5x + 2x + 2 ≤ 23

Combine like terms.

7x + 2 ≤ 23

Subtract 2 from both sides.

7x ≤ 21

Divide both sides by 7

x ≤ 3

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Will mark you as brainliest. If your good with polynomials.
kobusy [5.1K]
To solve/simplify this all you have to do is group like terms (the x^2's with each other, the x's with each other, and the normal numbers, -8)

14x^2-8+5x-6x^2+2x

group the x^2 (add 14x^2 to -6x^2)

8x^2-8+5x+2x

group the x's together (add 5x and 2x together)

8x^2+7x-8

Your answer will be d) 8x^2+7x-8



4 0
4 years ago
Will mark Brainlest!! <br>Help Please!<br>(1). find the domain and range of the following <br>​
miss Akunina [59]

Answer:

Step-by-step explanation:

You have the domain. It is given as -1≤x≤1

Now all you have to do is figure out the range which is the y value. At first glance I think it might be 3, but that does not look very logical. I'll post this much of it now and be back in under an hour with a more complete answer.

Of course! How silly of me. There is a minimum of y = 1 in the range which comes from x = 0

I've included a graph so you can see how this all works.

So the range = 1 ≤ y ≤ 3

5 0
3 years ago
Help me with this please. ​
riadik2000 [5.3K]

9514 1404 393

Answer:

  x ≈ 9.8

Step-by-step explanation:

The relevant trig relation is ...

  Tan = Opposite/Adjacent

Filling in the given values gives ...

  tan(59°) = x/5.9

Multiplying by 5.9, we have ...

  x = 5.9×tan(59°) ≈ 9.8

3 0
3 years ago
Can someone pls help me with this question. Ill give brainliest!!
creativ13 [48]

Answer:

  • Keep plugging in the points and see the ones that work, for example, (-1,7)
  • y=5x+12\\(7)=5(-1)+12\\7=7 true, so select it
  • Keep doing that for the rest of them , some like (3,15) won't work so you just have to keep testing each point.
5 0
3 years ago
Read 2 more answers
Find the solutions of the quadratic equation -9c² +2 +3 = 0.
Tresset [83]

Given that,

An equation : -9c² +2c +3 = 0

To find,

Find the value of x.

Solution,

We have, -9c² +2c +3 = 0

We can solve it using the formula as follows :

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Here, a = -9, b = 2 and c =3

Put the values,

c=\dfrac{-2\pm \sqrt{(2)^2-4(-9)(3)}}{2(-9)}\\\\c=\dfrac{-2+\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}, \dfrac{-2-\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}\\\\c=-0.47, 0.69

So, the solution are -0.47 and 0.69.

8 0
3 years ago
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