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IRINA_888 [86]
3 years ago
14

a student rents an apartment for the acdemic year(two semester) with three friends. The rent for the entire academic year is 10,

080. Each semester, the student receives a bill for his share of the rent. if he and his friends divide the rent equally, how much must he pay each semester?​
Mathematics
1 answer:
Lyrx [107]3 years ago
4 0
$1260

10,080/2= 5040
5040/4= 1260
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5 times marys age is the same as 28 less than 7 times her age. Find her age
Gnom [1K]

setup a simple algebraic equation and solve.

5x = 7x-28

-5x   -5x

0=2x-28

+28  +28

28=2x

Now divide both sides by 2 and you get that she is 14

3 0
3 years ago
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Identify the coefficient(s), constants, and number of terms for the following expression:
shusha [124]
The given expression is: 4 x^{2} -5

So, there are two terms in the expression
1) 4 x^{2}
2) -5

The constant term is -5. 
The co-efficient of 4 x^{2} is 4.
7 0
3 years ago
A dairy farm uses the somatic cell count (SCC) report on the milk it provides to a processor as one way to monitor the health of
Eva8 [605]

Answer:

t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37  

p_v =P(t_{4}>2.37)=0.038  

If we compare the p value and a significance level assumed \alpha=0.1 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.  

Step-by-step explanation:

Data given and notation

\bar X=250000 represent the sample mean  

s=37500 represent the standard deviation for the sample

n=5 sample size  

\mu_o =210250 represent the value that we want to test  

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the mean is higher than 210250, the system of hypothesis would be:  

Null hypothesis:\mu \leq 210250  

Alternative hypothesis:\mu > 210250  

Compute the test statistic  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37  

Now we need to find the degrees of freedom for the t distirbution given by:

df=n-1=5-1=4

Conclusion

Since is a one right tailed test the p value would be:  

p_v =P(t_{4}>2.37)=0.038  

If we compare the p value and a significance level assumed \alpha=0.1 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.  

6 0
3 years ago
Suppose the average yearly salary of an individual whose final degree is a​ master's is ​$45 thousand less than twice that of an
Lera25 [3.4K]

Answer:

<h2>$58500</h2>

Step-by-step explanation:

 let the degree holder earn  x

 then a masters degree holder earns= (2x-45,000)

the comnined amount of the two degree holders=   (2x-45,000)+x

2x-45000+x=117000

3x=117000+45000

3x=162000

x=162000/3

x=$54000

so bachelor'sdegree hold earns= $54000

a masters degree holder earns= (2(54000)-45,000)

a masters degree holder earns= (108000-45,000)

a masters degree holder earns=$63000

the average= (54000+63000)/2

the average= (117000)/2

the average=$58500

6 0
3 years ago
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