Given:
Length of the rectangle = x + 21
Width of the rectangle = 5
To find:
Perimeter and area of the rectangle
Solution:
Perimeter = 
Perimeter 
units
Area = length × width
Area 
square units
Substitute perimeter is 100 and find the value of x:
Subtract 52 from both sides.
Divide by 2 on both sides, we get
x = 24
Substitute area is 200 and find the value of x:
Subtract 105 from both sides.
Divide by 5 on both sides, we get
x = 19
If the perimeter is 100, then the value of x is 24.
If the area is 200, then the value of x is 19.
Since we know that length is twice the width, we can say that:
Perimiter = 2(twice the width) + 2(width)
Therefore, P = 2(2w) +2(w)
this simplifies to P=6w
Sine P=180, 160 = 6w, so w = 30
Because length is twice the width, length = 2 * width, or 2*30, which is 60
Therefore:
length = 60
width = 30
Answer:
15 oatmeal cookies
Step-by-step explanation:
Without writing it out, a method you could use to figure this out is by first dividing 25 by 5, which is 5. Next, multiply the numerator, 3, by 5 to get 15.
Therefore, 15 of the 25 cookies were oatmeal cookies.
Answer:
m∠SQR = 74°
Step-by-step explanation:
Points P, Q and R are collinear.
Therefore, angles PQR and angle RQS are the linear pair of angles.
Since linear pair of angles are supplementary angles.
m∠PQR + m∠RQS = 180°
By substituting the measures of the given angles,
(3m + 1) + (2m + 4) = 180
5m + 5 = 180
5m = 180 - 5
5m = 175
m = 
m = 35
Since, m∠SQR = (2m + 4)°
= (2×35) + 4
= 74°
Therefore, m∠SQR = 74° is the answer.
