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ANTONII [103]
3 years ago
10

Green seed pods are dominant to yellow and tall plants are dominant to short. If two plants are homozygous for their green seed

pods and are short are crossed, what percentage of the plants would have green seed pods? (if the answer is 5, write it as 5% or in fraction form).
Please help.

Biology
1 answer:
Vlada [557]3 years ago
6 0

Answer:

100%

Explanation:

This is a cross involving two different genes; one coding for seed pod color and the other for height in a plant. The allele for green seed pods (G) is dominant over the allele for yellow seed pod (g) in the first gene while the allele for tallness (T) is dominant over the allele for shortness (t) in the second gene.

According to the question, the two crossed plants are homozygous for their green seed pods and are short. Being homozygous for the green pod means that the parent plant will have a GG genotype for the first gene. A short plant exhibits the recessive trait, hence, will possess an homozygous recessive genotype i.e. tt. Therefore, the genotype of both parents crossed is: GGtt.

Each parent will undergo meiosis to produce gametes with the following allelic combinations: Gt, Gt, Gt and Gt. Using these gametes in a punnet square (see attached image), 16 possible offsprings will be produced and all offsprings will have the genotype: GGtt.

A GGtt offspring will phenotypically possess green seed pods and short traits. Since all the offsprings possess this green seed pod trait, hence, 100% of the offsprings have green seed pods

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Explanation:

To answer this question, we need to understand first that what is gene expression. Gene expression is a process in which genetic information is transcribed first to RNA and then into proteins. During transcription stage, only active genes would be transcribed to RNA and all other DNA material don't transcribe at all. Now, if there is an infection, host cell would express only those genes which would actively take part in the defense mechanism, e.g. R-genes, genes involved in production of reactive oxygen species, etc. Hence, to monitor the infection rate, we will look at the RNA-based genome. To do this, we will extract the total RNA and then would sequence it. Then we will annotate the genes and check the relative abundance (differential expression). Finally, we would have a clear that these genes were active against the infection. By doing temporal sampling and sequencing, we would be able to measure the rate as well.

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Answer:

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