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pishuonlain [190]
3 years ago
13

Helpp plss ill give anything

Mathematics
1 answer:
DIA [1.3K]3 years ago
3 0

Answer:is it a yes or no answer

Step-by-step explanation:

?????

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Akira used 10 centimeters to wrap 5 presents. How many presents did Akira wrap if she used 18 centimeters of tape? Solve using u
bezimeni [28]
Lets simplify this by dividing by 5
5p/5=1
10cm/5=2
So each present she used 2cm of tape for so... 
she must have wrapped 9 presents in total because, 
18/2=9
6 0
4 years ago
Which number would be 16,000 when rounded to the nearest thousand: 15,472 or 15,518 or 16,511 or 16,739?
Anna11 [10]
15,518, because it is over 15,500 and below 16,499.999999...
7 0
3 years ago
Read 2 more answers
Find the volume of the cone whose base is shown and whose altitude is 8 meters.
Aloiza [94]
\bf \textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}\implies V=\stackrel{base~area}{\pi r^2}\cdot \cfrac{1}{3}\stackrel{height}{h}\\\\
-------------------------------\\\\
\textit{base of this cone}\\\\
B=\stackrel{a~square}{5\cdot 5}+\stackrel{semi-circle}{\frac{\pi r^2}{2}}\implies B=25+\frac{\pi 3^2}{2}\\\\\\ B=\stackrel{square}{25}+\stackrel{semi-circle}{\frac{9\pi }{2}}
\\\\\\
\textit{height of this cone is just 8}\\\\
-------------------------------\\\\

\bf \textit{volume of this cone}\\\\
V=B\cdot \cfrac{1}{3}h\implies V=\left( 25+\cfrac{9\pi }{2} \right)\left( \cfrac{8}{3} \right)
\\\\\\
V=\cfrac{200}{3}+\cfrac{3\pi\cdot 4 }{1}\implies V=\cfrac{200}{3}+12\pi
7 0
4 years ago
The function g(x) is a transformation of the quadratic parent function, fx):
77julia77 [94]

Answer: D

Step-by-step explanation:

The graph is narrower, so the coefficient of x^2 has an absolute value more than 1.

  • Eliminate B and C.

Also, because g(x) opens down, the coefficient of x^2 is negative.

  • Eliminate A.

This leaves D as the answer.

6 0
2 years ago
PLSSS HELP ME WITH MATH
labwork [276]

Step-by-step explanation:

always remember, equations and inequalities are like a scale with 2 pans (left and right).

a variable is like a placeholder, an empty spot on the pans. and the expressions on both sides are kind of the conditions for the things to put in these empty spots so that the status of the scale stays unchanged.

for an equation the scale has to stay balanced all the time.

and in an inequality one side is heavier that the other (it normally does not matter how much heavier) with "<" or ">" signs, or the scale can be also balanced with "<=" or ">=" signs. just the other side must never be heavier.

A

so, in our case here

2x - 5 = 3

yes, the solution (the ONLY solution, actually) is x = 4. no other value of x allows the scale to be balanced.

2x - 5 >= 3

well, since it is a ">=" sign, we can be lazy and treat it like the equation above, and x = 4 is therefore a valid solution for the inequality too.

but so is every other value of x that makes the left side "heavier". what about e.g. 5 ?

2×5 - 5 >= 3

10 - 5 >= 3

5 >= 3

true, great ! so, e.g. x = 5 is also a valid solution.

what else ?

let's simplify the inequality

2x - 5 >= 3

2x >= 8

x >= 4

so, really every value of x that is greater or equal to 4 is a valid solution for the inequality.

B

-2x - 5 = 3

yes, the solution (the ONLY solution, actually) is x = -4. no other value of x allows the scale to be balanced.

-2x - 5 >= 3

well, since it is a ">=" sign, we can be lazy and treat it like the equation above, and x = -4 is therefore a valid solution for the inequality too.

but so is every other value of x that makes the left side "heavier". what about e.g. -5 ?

-2×-5 - 5 >= 3

remember, -×- = +

10 - 5 >= 3

5 >= 3

true, great ! so, e.g. x = -5 is also a valid solution.

what else ?

let's simplify the inequality

-2x - 5 >= 3

-2x >= 8

x <= -4

a multiplication or division by a negative value flips the inequality sign, because such an operation makes a light weight heavy and a heavy weight light.

so, really every value of x that is less or equal to -4 is a valid solution for the inequality.

3 0
2 years ago
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