Answer:
GH¢2082.12
Step-by-step explanation:
Let "a" represent the amount invested at 12%. Then (a+580) is the amount invested at 14%. The total amount invested (t) is ...
t = (a) +(a +580) = 2a+580
Solving for a, we get
a = (t -580)/2
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The accumulated amount from the investment at 12% is 1.12a. And the accumulated amount from the investment at 14% is 1.14(a+580). Together, these accumulated amounts total GH¢2358.60.
1.12(t -580)/2 +1.14((t -580/2 +580) = 2358.60
0.56t -0.56(580) +0.57t -0.57(580) +1.14(580) = 2358.60 . . . remove parens
1.13t + 5.8 = 2358.60 . . . . . . . . . simplify
1.13t = 2352.80 . . . . . . . . . . . . . . subtract 5.8
t = 2352.80/1.13 = 2082.12 . . . . divide by the coefficient of t
Mr. Azu's total investment was GH¢2082.12.
Micah saves 150 which means he has 30 *5 dollars
his parents will give him 300
176
+241=
417 There are 417 kids at school.
I am not sure what you mean by placing the first digit, but I am going to assume you need help with this division problem.
We are dividing 315 by 9
First figure out how many times 9 goes into 31.
3 times right?
Now do 9 * 3
9 * 3 = 27
Subtract 27 from 31
31-27= 4
Now how many times does 9 go into 45?
5 times
Putting the 3 and the 5 together, we can conclude that the answer is 35
Answer:
none of above
Step-by-step explanation: