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natta225 [31]
3 years ago
10

10 students are standing equidistant from the center of a classroom. they are all holding hands to begin with. they must go and

shake hands with all other students whose hands they are not holding. no handshake will occur more than once. how many handshakes will take place? ​
Mathematics
2 answers:
ozzi3 years ago
4 0

Answer:

35

Step-by-step explanation:

i dont know how to explain how i got the anwser

Alja [10]3 years ago
4 0

Answer:

45 handshakes will take place in total in the party

Step-by-step explanation:

Total number of students who attended the party = 10

Number of students needed to make one handshake = 2

Given that : no handshake will occur more than once.

⇒ No repetition of handshakes will be there.\

We need to find the total number of handshakes that took place in the party

\implies\text{Total number of handshakes = }_2^{10}\txterm{C}

\implies\text{Total number of handshakes = }\frac{10!}{2!\times 8!}

\implies\text{Total number of handshakes = }\frac{10\times 9}{2}

\implies\text{Total number of handshakes = }45

Therefore, 45 handshakes will take place in total in the party

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olga_2 [115]

Answer:

18.5

Step-by-step explanation:

First we plug in the number

-1 1/2 is the same as -1.5

Plugging this in we will have:

15(-1.5) + 4 =

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5 0
3 years ago
A 5×6 rectangular grid with unit cells is given. Let A(0, 0) and B(5, 6) be the bottom-left corner and top-right corner, respect
harina [27]

Answer:

462 paths from A to B

Step-by-step explanation:

The question is incomplete. However, a possible question is to determine the number of possible paths on the grid map.

The first step is to represent the grid map itself. (See attachment 1)

From the question, we understand that:

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There are a several number of ways to navigate through. However, one possible way is in attachment 2

In attachment 2,

  • R represents the right movement
  • U represents the up movement

And we have:

R = 5     and    U = 6

The number of possible paths (N) is then calculated as:

N = \frac{(N + U)!}{N!U!}

Substitute values for N and U

N = \frac{(5 + 6)!}{5!6!}

N = \frac{11!}{5!6!}

N = \frac{39916800}{120 * 720}

N = \frac{39916800}{86400}

N = 462

<em>Hence, there are 462 possible paths from A to B</em>

4 0
3 years ago
The sum of two numbers is 62, and their difference is 12. What are the numbers?
nordsb [41]
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Step-by-step explanation:

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Step-by-step explanation:

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