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Agata [3.3K]
3 years ago
5

Write the fraction that names each part. Write a fraction in worlds and in number to name the shaded part.

Mathematics
1 answer:
Afina-wow [57]3 years ago
5 0
Idk this answer because no triangles are shaded.

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Determine if the following relation represents a function or not.
artcher [175]

Answer:

It is a function.

Step-by-step explanation:

Functions are relations in which one domain value is assigned to exactly one range value. The x-value must not repeat in the relation set for it to be a function.

{(2,3), (4,3), (6,3), (5,9), (3,9)}

There are no repeating x-values given.

The relation should be a function.

Hope this helps.

6 0
3 years ago
Greg spent 6.4 hours working with his dad one Saturday. If his dad paid him$45.76, how much did Greg make per hour?
nordsb [41]

Answer:

$7.15

Step-by-step explanation:

The best way to solve this is by crossing out the data you don't need so you're left looking at the key pieces to put the equation together. If his dad paid him $45.76 for 6.4 hours, then all you need to do is divide 45.76 by 6.4. (Hint: Use a calculator, it makes it ten times faster than trying to write it out!)

45.76 ÷ 6.4 = 7.15

So Greg made $7.15 an hour working with his dad.

6 0
3 years ago
Prove the trigonometric identity
Annette [7]

Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1

Lets solve the bottom most part first:

1-\frac{1}{1-sec^2x} \\\\

Take LCM

1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}

now break the LCM

\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1

because 1/tan = cot x

and furthermore,

cot^2x+1\\cosec^2x

now we solve the above part and replace the bottom most part that we solved with cosec^2x

\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x

Hence proved! :D

4 0
3 years ago
A premature infant is gaining 2.5 ounces a day. At that rate, how many days will it take for him to gain 8 ounces
Ann [662]

Answer:

3.2 days

Step-by-step explanation:

All you have to do is divide 8 by 2.5

8 ÷ 2.5 = 3.2

5 0
3 years ago
PLEASE ANSWER ASAP
SOVA2 [1]

Answer:

x - 2 ≥ 0

Step-by-step explanation:

The expression under the square root cannot be negative, thus

x - 2 ≥ 0 , that is

x ≥ 2

4 0
3 years ago
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