The solution to the systems if equation y = 4x - 5, y = 2x + 3 is (x, y) = (4, 11)
<h3>Equation</h3>
y = 4x - 5
y = 2x + 3
4x - 5 = 2x + 3
4x - 2x = 3 + 5
2x = 8
x = 8/2
x = 4
y = 4x - 5
= 4(4) - 5
= 16 - 5
y = 11
Therefore, the solution to the system of be equation is x = 4 and y = 11
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Answer:
(f*g)(x) = 3x^3 + 6x^2
Step-by-step explanation:
Since we are looking for the result of multiplying the equations (f*g), we must multiply the right sides together
(f*g)(x) = (3x^2)(x+2)
To get from here to the solutions, we must multiply the first term by all parts in the second term
3x^2 * x = 3x^3
3x^2 * 2 = 6x^2
from there, just put them back in the equation
(f*g)(x) = 3x^3 + 6x^2
Answer:
=−4
Step-by-step explanation:
10−10−1−3
=0−1−3
=−1−3
=−4
Answer:
a
4,5,8,11 are the domain
Step-by-step explanation:
x is always the domain, input and It could also be a function but I don't think that only four five eight and 11 are functions so I would go with a
