Answer:
62 and 56 or 59 and 59
Step-by-step explanation:
62, 62, 56
or
62, 59, 59
Answer:
a. z = 2.00
Step-by-step explanation:
Hello!
The study variable is "Points per game of a high school team"
The hypothesis is that the average score per game is greater than before, so the parameter to test is the population mean (μ)
The hypothesis is:
H₀: μ ≤ 99
H₁: μ > 99
α: 0.01
There is no information about the variable distribution, I'll apply the Central Limit Theorem and approximate the sample mean (X[bar]) to normal since whether you use a Z or t-test, you need your variable to be at least approximately normal. Considering the sample size (n=36) I'd rather use a Z-test than a t-test.
The statistic value under the null hypothesis is:
Z= X[bar] - μ = 101 - 99 = 2
σ/√n 6/√36
I don't have σ, but since this is an approximation I can use the value of S instead.
I hope it helps!
5x-29>-34
5x>-5
x>-1
x<1
2x+31<29
2x<-2
x<-1
x>1
12 because if you take 2 and add it to 10 you get 12
P = 150w
In words, 1 seed packet (p) is 150 wild flowers (w)