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4 years ago

Find the equation of the line.

Mathematics

1 answer:

s2008m [1.1K]4 years ago

8 0

Answer:

y = $-\frac{1}{3}x+5$

Step-by-step explanation:

Let the equation of the given line is,

y = mx + b

where 'm' = slope of the line

b = y-intercept of the line

Since slope of a line passing through two points $(x_1, y_1)$ and $(x_2, y_2)$ is represented by,

m = $\frac{y_2-y_1}{x_2-x_1}$

If the points are (0, 5) and (-3, 6),

Slope of the line 'm' = $\frac{6-5}{-3-0}$

= $-\frac{1}{3}$

y-intercept of the line 'b' = 5

Therefore, equation of the given line will be,

y = $-\frac{1}{3}x+5$

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Can someone please help?

lord [1]

Answer:

Well a midpoint makes the cutter segment or Line in exactly in half. So the two lines cutted are equal. In this case t is the midpoint. PT and TQ are equal. So you have two expressions, make then equal to each other since they are congruent.

6x+4=8x-8

12=2x

x=6

Now PT is 6x+4

So we subsitute x for 6 since x=6

6*6+4

PT is 40

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3 years ago

Systems of Equations... y = 3x+1 y=x+5

dangina [55]

Answer:

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3 years ago

15 of 15 Find the size of the final unknown interior angle in a polygon whose other interior angles are: 162°, 115°, 125°, 148°

alexandr1967 [171]

Answer: 147 Degrees

Step-by-step explanation

The size of the final unknown interior angle in a polygon is 147 degrees.

Given that,

The other interior angles are 162°, 115°, 120°, 148° and 85°.

We assume that there is an equation (2n - 4) 90.

Here n be 7.

Based on the above information, the calculation is as follows:

= (2n - 4) 90

= ((2) (7) - 4) 90

= 10 (90)

= 900

Now the size of the unknown interior angle is

= 900-(162+125+148+105+98+115)

= 900 - 753

= 147°

Therefore we can conclude that the size of the final unknown interior angle in a polygon is 147 degrees.

6 0

2 years ago

Given that f(x) = x^2-3/2

IRINA_888 [86]

Step-by-step explanation:

a) f(3)=3^2 - 3/2

=9-3/2

=15/2

8 0

3 years ago

I’m not sure how to do this

Brums [2.3K]

Answer: lim as x → -5 of f(x) and g(x) = 300

Domain of f(x) and g(x) is All Real Numbers

f(-5) = 200

g(-5) = 300

Step-by-step explanation:

The limit of f(x) as x approaches -5:

$f(x) =\dfrac{4x^3+500}{x+5}\\\\\\.\qquad =\dfrac{4(x^3+125)}{x+5}\\\\\\.\qquad =\dfrac{4(x^3+5^3)}{x+5}\qquad \text{we can factor the cubic}\\\\\\.\qquad =\dfrac{4(x+5)(x^2-5x+25)}{x+5}\\\\\\.\qquad =4(x^2-5x+25)\\\\\\\text{as x approaches -5, f(x) = }4[(-5)^2-5(-5)+25]\\\\.\qquad \qquad \qquad \qquad \qquad =4(25 + 25 + 25)\\\\.\qquad \qquad \qquad \qquad \qquad =4(75)\\\\.\qquad \qquad \qquad \qquad \qquad =300$

The limit of g(x) as x approaches -5:

g(x) = 4x² - 20x + 100

= 4(-5)² - 20(-5) + 100

= 100 + 100 + 100

= 300

There is a restriction at x = -5 for f(x), however, that discontinuity has been filled with the 200 at x = -5. So the domain is ALL REAL NUMBERs.

There are no restrictions on x for g(x) so the domain is ALL REAL NUMBERs.

5 0

3 years ago