AB = 12, BC = 8x - 2, AC = 10x

If 4m + 1 = 7 then 4m = 6

sergij07 [2.7K]

Answer:

2) Subtraction Property of Equality Properties

General Formulas and Concepts:

Pre-Algebra

Addition Property of Equality - Adding on both sides
Subtraction Property of Equality - Subtracting on both sides
Multiplication Property of Equality - Multiplying on both sides
Division Property of Equality - Dividing on both sides
Transitive Property - If a = b and b = c, then a = c
Symmetric Property - If a = b then b = a

Step-by-step explanation:

Step 1: Define

4m + 1 = 7 → 4m = 6

Step 2: Identify

We see that we subtracted on on both sides of the equation. Therefore, we would have to use the Subtraction Property of Equality. Therefore, 2 is our answer.

6 0

3 years ago

50 POINTS REWARD!! please answer all of the following questions correctly:

Pani-rosa [81]

$\frac{3x-2}{x^{2}-2x-3} -\frac{1}{x-3}$

factorising the first denominator

x²-2x-3 = x² -3x+x-3 = (x+1)(x-3)

(a) $\frac{3x-2}{(x+1)(x-3)} - \frac{1}{x-3}$

finding LCD

(b) LCD of (x-3)(x+1) and (x-3) is (x-3)(x+1)

(c)

$\frac{3x-2}{(x-3)(x+1)} -\frac{x+1}{(x-3)(x+1)}$

(d)

$\frac{3x-2-(x+1)}{(x-3)(x+1)}$

$\frac{3x-2-x-1}{(x-3)(x+1)}$

$\frac{2x-3}{(x-3)(x+1)}$

5 0

4 years ago

Read 2 more answers

Chris pays a fee if the bank balance falls below $10 on the statement dae. Prior to the statement date her balance was -3.46. Th

Zina [86]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Balance prior to statement date = - 3.46

Minimum bank balance to avoid penalty = $10

The amount of deposit, d made in time in other to avoid penalty fee?

Minimum amount that most have been deposited, d :

Balance prior to statement + d ≥ minimum bank balance to avoid penalty

-3.46 + d ≥ 10

d ≥ 10 + 3.46

d ≥ 13.46

Hence, the minimum amount that must have been deposited to avoid penalty is 13.46

4 0

3 years ago

A rectangle has its vertices at (-4, -3), (-4,7), (1,7), (1, -3). What part, in percent, of the rectangle is located in Quadrant

Rasek [7]

Consider the attached figure. The whole rectangle is ABCD, while AEGF is the part located in the third quadrant. In fact, this quadrant is composed by all the points with both coordinates negative.

To answer the question, let's compute the area of the two rectangles and see what part of ABCD is AEGF.

A and B have the same x coordinate, so the length of AB is given by the absolute difference of their y coordinates:

$\overline{AB} = |A_y-B_y| = |-3-7| = |-10| = 10$