ITS A HEXAGON
BECAUSE IT HAS 6 SIDES
Answer:
20:46 or 20 to 46
Step-by-step explanation:
There are 20 girls on the team so theres your first number then you add the girls and boys to get the total number of players (46) and write out your ratio
Using the given discrete probability distribution, it is found that the probability that a randomly selected student has a grade higher than a C is given by:
P(X > 2).
<h3>What is the discrete probability distribution for the grade?</h3>
From the table, it is given by:
- P(X = F) = P(X = 0) = 0.04.
- P(X = D) = P(X = 1) = 0.05.
- P(X = C) = P(X = 2) = 0.17.
- P(X = B) = P(X = 3) = 0.31.
- P(X = A) = P(X = 4) = 0.43.
Grades A and B are greater than C, hence the probability of getting a grade higher than C is given by:
P(X > C) = P(X = A) + P(X = B) = P(X = 3) + P(X = 4) = P(X > 2).
More can be learned about discrete probability distributions at brainly.com/question/24855677
the general equation for velocity in terms of acceleration and displacement is: v² = v₀² + 2ax.
Solve for a: a = (v² - v₀²)/(2x).
You are given v₀ and v, and x is easy to calculate since you are given its initial and final values. The rest is just arithmetic.
(note also: SI expressions have a required space between the coefficient and the unit symbol. Thus you should have things such as “15 m” and “-2 m·sˉ¹” instead of “15m” and “-2m·sˉ¹”.)
Answer:
Number of cheaper dresses sold is 35
Number of expensive dresses sold is 15
Step-by-step explanation:
Given:
Cost of cheaper dresses = $90
Cost of expensive dresses = $140
Total cost of the dresses = $5250
To Find:
Number of cheaper dress = ?
Number of expensive dress = ?
Solution:
Let
The number of cheaper dresses be x
The number of expensive dresses be y
(Number of cheaper dresses X cost of cheap dress) + (Number of Expensive dresses X cost of expensive dress) = $5250
= $5250
It is given that the 20 more of the cheaper dresses than the expensive dresses is sold
So,
number of cheaper dress = 20 + number of expensive dress
x = 20 + y---------------------------------------(1)
![(20+y) \times90 +y \times 140 = 5250 = 5250](https://tex.z-dn.net/?f=%2820%2By%29%20%5Ctimes90%20%2By%20%5Ctimes%20140%20%3D%205250%20%3D%205250)
![(20 \times 90 +y\times 90) +y \times 140= 5250](https://tex.z-dn.net/?f=%2820%20%5Ctimes%2090%20%2By%5Ctimes%2090%29%20%2By%20%5Ctimes%20140%3D%205250%20)
![1800 + 90y+ 140y = 5250](https://tex.z-dn.net/?f=1800%20%2B%2090y%2B%20140y%20%3D%205250%20)
![1800 + 230y = 5250](https://tex.z-dn.net/?f=1800%20%2B%20230y%20%3D%205250%20)
![230y =5250 -1800](https://tex.z-dn.net/?f=%20230y%20%3D5250%20-1800)
![230y = 3450](https://tex.z-dn.net/?f=%20230y%20%3D%203450%20)
![y = \frac{3450}{230}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B3450%7D%7B230%7D)
y = 15
Substituting y in (1)
x = 20 +15
x= 35