Question

Suppose Pr(A)=0.25 and Pr(B)=0.48, where A and B are mutually exclusive. Find Pr(A ? B).

Answer 1

Answer with explanation:

It is given that, two Events , A and B are mutually exclusive.

→Pr (A ∩ B)=0

→Pr(A)=0.25

→Pr (B)= 0.48

So, Pr (A ∪ B)=Pr (A)+ Pr (B)-Pr(A∩B)

                    =0.25 +0.48-0

                    =0.73

Answer 2

Answer:  The required value is P(A ∪ B) = 0.73.

Step-by-step explanation:  Given that A and B are two mutually exclusive events where

$P(A)=0.25~~~\textup{and}~~~P(B)=0.48$

We are to find the following probability :

P(A ∪ B).

We know that

the intersection of two mutually exclusive events is null event. That is,

A ∩ B = ∅     ⇒  P(A ∩ B) = 0.

From the laws of probability, we have

$P(A\cup B)=P(A)+P(B)-P(A\cap B)=0.25+0.48-0=0.73$

Thus, the required value is P(A ∪ B) = 0.73.