6.2:
fraction: .2 = 0.20 = 20/100
fraction: 6 20/100
Word form: six point two
two and five hundredths
fraction: 2 5/100
decimal form 2.05
hope this helps
Answer:
The smallest integer is -4.
Step-by-step explanation:
Let the smallest integer be x.
Since the integers are all multiples of 4, they are
=> x, x+4, x+8, x+12 and x+16
=> x + x+4 + x+8 + x+12 + x+16 = 20
=> 5x + 40 = 20
Subtract 40 from both sides of the equation
5x +40 - 40 = 20 - 40
5x = -20
Divide both sides by the coefficient of x(which is 5)
x = -4
∴ the smallest integer is -4.
Hope this helps!!!
Answer:
52 ft
Step-by-step explanation:
the answer is c
<h3>
Answer: choice C) 15</h3>
Simplify the left side to get
2(4+x)+(13+x)
2(4)+2(x) +13+x
8+2x+13+x
3x+21
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So the original equation
2(4+x)+(13+x) = 3x+k
turns into
3x+21 = 3x+k
------------
Subtract 3x from both sides
3x+21 = 3x+k
3x+21-3x = 3x+k-3x
21 = k
k = 21
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If k = 21, then the original equation will have infinitely many solutions. This is because we will end up with 3x+21 on both sides, leading to 0 = 0 after getting everything to one side. This is a true equation no matter what x happens to be.
If k is some fixed number other than 21, then there will be no solutions. This equation is inconsistent (one side says one thing, the other side says something different). If k = 15, then
3x+21 = 3x+k
3x+21 = 3x+15
21 = 15 .... subtract 3x from both sides
The last equation is false, so there are no solutions here.
note: if you replace k with a variable term, then there will be exactly one solution.
Replace each of the x values given to see if they give 0.
0=(2/3)³+(2/3)²-1
0=(8/27)+(4/9)-1
0≠-0.259
0=(1)³+(1)²-1
0≠1
Therefore, you can see that the solution would have to be between 2/3 and 1.
Hope I helped :)
