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tresset_1 [31]
3 years ago
7

V =

ddle" class="latex-formula">π³
The equation above can be used to calculate the volume V, of a sphere with radius r.


If the volume of a sphere is 288πcm3, what is the radius of the sphere in centimeters?


Please show solution. Giving brainliest + 20 points!
Mathematics
1 answer:
motikmotik3 years ago
7 0

Answer:

The radius of the sphere is 6\ cm

Step-by-step explanation:

we know that

The volume of a sphere is equal to

V=\frac{4}{3}\pi r^{3}

In this problem we have

V=288\pi\ cm^{3}

substitute and solve for r

288\pi=\frac{4}{3}\pi r^{3}

simplify

288*3/4=r^{3}

r^{3}=216

r=6\ cm

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(GIVING BRAINLIEST!!!)
Blizzard [7]

Answer:

B) \displaystyle \frac{1}{16}

Step-by-step explanation:

\displaystyle \frac{1}{16} = \frac{\frac{1}{8}}{2} \\ \\ OR \\ \\ \frac{1}{8} \div 2 = \frac{1}{8} \times \frac{1}{2} = \frac{1}{16}

I am joyous to assist you at any time.

6 0
3 years ago
Can you plz do 6 and 7 and 10 it will be a lot for me
Mila [183]

36 ÷ 4 can be written as:

Thirty-six divided by four.

24 - (6 + 3) can be written as:

The difference of twenty-four and six plus three.

We'll use the expression x - 7 for this one.

The difference between a number and seven.

Hope this helps!


5 0
3 years ago
Helpl please urgent!! plzzzzzzzzzzzz
Elodia [21]

Answer:

45 in

Step-by-step explanation:

This look like the branch of the basic pythagorean triplet.

3, 4, 5 is a fundamental triplet.

if you multiply all three numbers by 9, you will get:

27, 36, 45

X = 45 in

Hope this helps :)

6 0
2 years ago
I need help with this problem. Given: BC = 10 inches AC = √50 inches m∠CBD = 60° m∠CAD = 90° Calculate the exact area of the sha
Nikitich [7]

Answer:

Area of the shaded region = 23.33 in²

Step-by-step explanation:

Area of a sector = \frac{\theta}{360}(\pi r^{2})

Where θ = Central angle subtended by an arc

r = radius of the circle

Area of the sector BCD = \frac{60}{360}(\pi) (10^{2})

                                       = 52.36 in²

Area of equilateral triangle BCD = \frac{\sqrt{3} }{4}(\text{Side})^2

                                                      = \frac{\sqrt{3} }{4}(10)^2

                                                      = 25\sqrt{3} in²

                                                      = 43.30 in²

Area of the shaded portion in ΔBCD = 52.36 - 43.3

                                                             = 9.06 in²

Area of sector CAD = \frac{90}{360}(\pi)(\sqrt{50})^2

                                 = 39.27 in²

Area of right triangle CAD = \frac{1}{2}(\text{Base})(\text{Height})

                                            = \frac{1}{2}(\text{AC})(\text{AD})

                                            = \frac{1}{2}(\sqrt{50})(\sqrt{50})

                                            = 25 in²

Area of the shaded part in the ΔACD = 39.27 - 25

                                                                         = 14.27 in²

Area of the shaded part of the figure = 9.06 + 14.27

                                                                = 23.33 in²

8 0
2 years ago
PLEASE HELP! I am doing Imagine Math and I need help with this question!
Vaselesa [24]
The bottom left option is when it is reflected over the x axis, the second to last option on the left is when it is reflected of the y axis, and the middle option is when it is reflected over the line y = x

Hope this helps :)
5 0
2 years ago
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