1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Kamila [148]
3 years ago
9

Is my answer correct and how do you know? I just graphed it , is there another way I could do it?

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
7 0
Note the general equation of a circle is x^2 + y^2 = r^2, with centre (0, 0) and radius: r.

So, our equation of a circle is (x + 3)^2 + (y - 1)^2 = 100

Subtract 100 from both sides and plug in the points. If it equals to 0, then the points satisfy the equation of the circle (ie lies on the circle)
Anna35 [415]3 years ago
7 0
Yes and yes,

the equation of a circle with a center at (h,k) with a radius of "r" is
(x-h)^2 +(y-k)^2=r^2

you know the center (h,k) is (-3,1) and r= 10, so you could plug in the answers and see which ones will match

A more intuitive method of doing it is to recognize that the given equation is like the pythagorean theorem. Also, know that a 3-4-5 is a right triangle and thus a 6-8-10 is also a right triangle.
since radius is 10, that means the other 2 values (x-x1) and (y-y1) must be equal to 6 and 8, so find the answer that will give yuo 6 and 8
You might be interested in
Which is the graph of the equation y-1 =
Margaret [11]

(1×3=3×1(-3,

Step-by-step explanation:

8$$_899(+¿????

7 0
3 years ago
Define equation. Give an example of two equivalent equations.
mario62 [17]
A statement that has mathematical expressions that are equal.
Examples:
2+1=3
11x4=44
8 0
3 years ago
Can someone help me ?
prisoha [69]
I’m pretty sure there are infinite solutions as the system of equations are equivalent to each other.
7 0
3 years ago
Read 2 more answers
69. REAL-WORLD APPLICATIONS
svp [43]

Answer:

Cost of per session the average rate is $45.

Step-by-step explanation:

It is given that a gym membership with two personal training session cost $125, while gym membership with five personal training sessions cost $260.

It is required to find what is the cost per session.

Step 1 of 1

It is given that a gym membership with two personal training session cost $125, while gym membership with five personal training sessions cost $260.

To find the cost of per session calculate the average rate.

Now let $f(x)$ be the cost per session use the for the average rate of change, and the input value is the number of personal traings x.

$m=\frac{f\left(x_{2}\right)-f\left(x_{1}\right)}{x_{2}-x_{1}}$$

Now substitute, $125 for $f\left(x_{2}\right), 260 for $f\left(x_{1}\right), 2$ for $x_{1}$ and 5 for $x_{2}$ then,

$m=\frac{260-125}{5-2}$\$$\begin{aligned}&=\frac{135}{3} \\&=45\end{aligned}$$

Cost of per session the average rate is $45.

3 0
2 years ago
amortization for house costs 35,000.00 at 6.5% interest for 10 years and payments of 400.00 were paid for 36 months what is the
UNO [17]

Answer:

$26,640.22

Step-by-step explanation:

8 0
2 years ago
Other questions:
  • Which values, when placed in the box, would result in a system of equations with no solution? Check all that apply.
    7·2 answers
  • If g(x) = 4(x - 2)2 - 4, complete the following statements.
    6·2 answers
  • Help me with these questions please!!!
    13·1 answer
  • −15x+60≤105 AND14x+11≤−31
    7·1 answer
  • if cos a = 1/3 then the positive value of tan 1/2a is? i did radical 2/3 over 4/3, but im not sure what to do now.
    7·1 answer
  • So I'm calculating the areas of squares and rectangles.
    10·1 answer
  • Divide. Write your answer as a fraction or a mixed number in simplest form.
    11·1 answer
  • Help please not too sure about this one?
    9·1 answer
  • The marked price of a textbook is $20. A school is given a 6.5% discount. Find the amount of money the
    13·2 answers
  • Find the inverse of the matrix using elementary row operations on the augmented matrix
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!