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Kamila [148]
3 years ago
9

Is my answer correct and how do you know? I just graphed it , is there another way I could do it?

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
7 0
Note the general equation of a circle is x^2 + y^2 = r^2, with centre (0, 0) and radius: r.

So, our equation of a circle is (x + 3)^2 + (y - 1)^2 = 100

Subtract 100 from both sides and plug in the points. If it equals to 0, then the points satisfy the equation of the circle (ie lies on the circle)
Anna35 [415]3 years ago
7 0
Yes and yes,

the equation of a circle with a center at (h,k) with a radius of "r" is
(x-h)^2 +(y-k)^2=r^2

you know the center (h,k) is (-3,1) and r= 10, so you could plug in the answers and see which ones will match

A more intuitive method of doing it is to recognize that the given equation is like the pythagorean theorem. Also, know that a 3-4-5 is a right triangle and thus a 6-8-10 is also a right triangle.
since radius is 10, that means the other 2 values (x-x1) and (y-y1) must be equal to 6 and 8, so find the answer that will give yuo 6 and 8
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Answer:

Step-by-step explanation:

what fraction?? she uses 1/6 of the construction paper

if you are referring to how much paper is left, its 2/6 aka 1/3

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iren2701 [21]
Itzzzzz 13/15 in simplest form
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What is the slope of the line that contains the points (-1, 8) and (2, -4)?
trapecia [35]

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-4

Step-by-step explanation:

The slope of a line given two points is given by

m = (y2-y1)/(x2-x1)

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4 years ago
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Solve for the variable x - 9 = 11
Strike441 [17]

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20

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3 0
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Ayuda por favor
sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos <em>similares</em>, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo <em>pequeño</em>) y AP'' (triángulo <em>grande</em>), así como de los lados AM y AB, así como los lados AN y AC, así como los <em>mismos</em> ángulos en la <em>misma</em> distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2     (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot  h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

#SPJ1

3 0
2 years ago
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