Overall dimensions of the page in order to maximize the printing area is page should be 11 inches wide and 10 inches long .
<u>Step-by-step explanation:</u>
We have , A page should have perimeter of 42 inches. The printing area within the page would be determined by top and bottom margins of 1 inch from each side, and the left and right margins of 1.5 inches from each side. let's assume width of the page be x inches and its length be y inches So,
Perimeter = 42 inches
⇒ 
width of printed area = x-3 & length of printed area = y-2:
area = 
Let's find 
:
= 
, for area to be maximum = 0
⇒ 
And ,
∴ Overall dimensions of the page in order to maximize the printing area is page should be 11 inches wide and 10 inches long .
Answer:
x²+22
Step-by-step explanation:
let the number= X
x²+22
Answer:
a
Step-by-step explanation:
Given
2| x - 3 | + 5 = 17 ( subtract 5 from both sides )
2| x - 3 | = 12 ( divide both sides by 2 )
| x - 3 | = 6
The absolute value function always returns a positive value but the expression inside can be positive or negative, that is
x - 3 = 6 OR -( x - 3) = 6
x - 3 = 6 ( add 3 to both sides )
x = 9
OR
-( x - 3) = 6 ← distribute left side
- x + 3 = 6 ( subtract 3 from both sides )
- x = 3 ( multiply both sides by - 1 )
x = - 3
As a check
Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.
x = 9 → 2|9 - 3| + 5 = 2|6| + 5 = (2 × 6) + 5 = 12 + 5 = 17 ← True
x = - 3 → 2|- 3 - 3| + 5 = 2| - 6 | + 5 = (2 × 6) + 5 = 12 + 5 = 17 ← True
Hence x = 9 or x = - 3 are the solutions → a
