Uhhh that doesn’t seem possible but then again i forgot simple math lol
We are given two binomials: x+4 , x^2-9.
x+4 can't be factored. Therefore, it is a prime.
Let us work on x^2-9.
9 could be written as 3^2.
Therefore, x^2-9 = x^2 - 3^2.
Now, we can apply difference of the squares formula to factor it.
We know a^2 -b^2 = (a-b) (a+b).
Therefore, x^2 - 3^2 can be factored as (x-3) (x+3).
So, x^2-9 is not a prime binomial because it can be factored as (x-3) (x+3).
Step-by-step explanation:
a(n) = a +(n-1)d
a=-5
d=5
a(n) = -5 +(n-1)5
=-5+5n-5
=5n-10
a(50) = -5 +(50-1)5
= 240
hope this helps
Answer:
6x^2+9x-6
Step-by-step explanation:
(3x+6)(2x-1)=6x^2+12x-3x-6=6x^2+9x-6
Answer:
A. 
B. Yes
Step-by-step explanation:
2*2*2=8cm cubed
8*12*10=960 which is greater than 800
