Answer:
The maximum height of the projectile is 90 ft
Step-by-step explanation:
Here, we want to get the maximum height reached by the projectile
The answer here will be the y-coordinate value of the vertex form of the given equation
so firstly, we have to write the equation in the vertex form
We have this as;
y = -16t^2 + 64t + 26
That will be;
y = a(x-h)^2 + k
y = -16(x-2)^2 + 90
where the vertex of the equation is;
(-h,k)
K
in this case is 90 and thus, that is the maximum height of the projectile
Answer:
1 / 36 ft³
Step-by-step explanation:
Length = 1/2 ft
Width = 1/6 ft
Height = 1/3 ft
The volume of the tank can be obtained using the relation :
Volume = Length * width * height
Volume = (1/2 * 1/6 * 1/3) ft³
Volume = 1 / 36 ft³
Answer:
16
Step-by-step explanation:
I dont really inderstand but i would say 16 because it is closer to adding up to 43 so yea
