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natali 33 [55]
3 years ago
10

Two congruent circles centered at points A and B each pass through the other circle's

Mathematics
1 answer:
coldgirl [10]3 years ago
8 0

Answer:

  60°

Step-by-step explanation:

We know triangle ABC is an equilateral triangle, since all of its side measures are the radii of the circles. That means angle BAC is 60°. Likewise, angle BAD is 60°, so arc CD is 120°.

The measure of inscribed angle CED is half the measure of the intercepted arc CD, so is ...

  ∠CED = 120°/2

  ∠CED = 60°

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Convert the polar equation to rectangular coordinates. (Use variables x and y as needed.)
Alinara [238K]
The standard conversion toolbox:
x=rcos(θ)
y=rsin(θ)

Here r=7csc(θ)
so 
x=7csc(θ)*cos(θ)=7cos(θ)/sin(θ)=7cot(<span>θ)
y=7csc(</span>θ)*sin(θ)=7sin(θ)/sin(<span>θ) = 7
therefore the rectangular coordinates are (7cot(</span><span>θ), 7)</span>
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3 years ago
PLEASEE HELPP Analyze these two graphs, which show the population growth (per thousands of people) of North Carolina and the Uni
Tju [1.3M]
I believe it’s A because if you notice the rate of population grow was in the 20,000s for the US in the 1840s, while NC was hitting 600 free people at that time.
5 0
3 years ago
Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif
algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64  

e) p_v =P(t_{118}  

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

\bar X_{O}=2.91 represent the mean for the Orange Coast

\bar X_{C}=2.96 represent the mean for the Coastline

s_{O}=0.05 represent the sample standard deviation for Orange Coast

s_{C}=0.03 represent the sample standard deviation for Coastline

n_{O}=60 sample size for Orange Coast

n_{C}=60 sample size for Coastline

\alpha=0.005 Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis:\mu_{O} \geq \mu_{C}  

Alternative hypothesis:\mu_{O} < \mu_{C}  

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=60+60-2=118  

Replacing the info we got:

t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64  

Part e

We can calculate the p value with this probability:

p_v =P(t_{118}  

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

5 0
3 years ago
Need help with number 3
marin [14]
IM THINKING B.)
HOPE ITS RIGHT LOL 
3 0
3 years ago
Round to nearest number 29 4/5
kaheart [24]
29.8 would be the number, but rounded would be 30
5 0
3 years ago
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