Two congruent circles centered at points A and B each pass through the other circle's
1 answer:
Answer:
60°
Step-by-step explanation:
We know triangle ABC is an equilateral triangle, since all of its side measures are the radii of the circles. That means angle BAC is 60°. Likewise, angle BAD is 60°, so arc CD is 120°.
The measure of inscribed angle CED is half the measure of the intercepted arc CD, so is ...
∠CED = 120°/2
∠CED = 60°
You might be interested in
The standard form of a line:
We have the equation of a line in the slope-point form:
use distributive property
add 3 to both sides
multiply both sides by 2
subtract x from both sides
change the signs