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scZoUnD [109]
3 years ago
15

Ivan bought 35 stamps. Some of these stamps cost $0.15 each, and the rest cost $0.40 each. If the total value of the stamps he b

ought is $7.25, determine the number of $0.15 stamps that Ivan bought.
Mathematics
1 answer:
3241004551 [841]3 years ago
6 0

Answer:

  27

Step-by-step explanation:

Let x represent the number of $0.15 stamps Ivan bought. Then the value of his stamps is ...

  0.15x +0.40(35-x) = 7.25

  -0.25x +14.00 = 7.25 . . . . . eliminate parentheses, collect terms

  -0.25x = -6.75 . . . . . . . . . . . subtract 14.00

  x = 27 . . . . . . . . . . . . . . . . . . divide by -0.25

Ivan bought 27 $0.15 stamps.

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Lizards can eat 45 ants per minute. How long would it take to eat 1,080 ants?
dsp73

Answer: 24 minutes!

Step-by-step explanation: As mentioned, it can eat 45 ants per minute, How long would it take to eat 1,080 ants?

It's simple, just divide 1080 by 45 and when you divide it, the answer is 24!

4 0
3 years ago
Which expression is equivalent to x - 5/3
soldier1979 [14.2K]

Answer:

\frac{1}{3}(3x-5)

Step-by-step explanation:

If you expand an equation you get its equivalent expression

6 0
3 years ago
There are three clubs at Redwood High School: Debate, Student council, and Key club. There are 1000 students in the school. And
hram777 [196]

Answer:

The number of students in the key club is 490

Step-by-step explanation:

The given parameters are;

The number of student in the school = 1000

The total number of student in the debate club = 310

The total number of student in the student council = 650

The total number of student who are in debate and student council = 170

The total number of student who are in both debate and the key club = 150

The total number of student who are in both student council and the key club = 180

The number of students who are in all three clubs = 50

Therefore, we have;

Let A represent the number of students in the debate club

Let B represent the number of students in the student council

Let C represent the number of students in the key club

We have;

n(A∪B∪C) = n(A) + n(B) + n(C) -  n(A∩B) - n(B∩C) - n(C∩A) + n(A∩B∩C)

Where;

n(A∪B∪C) = 1000

n(A) = 310

n(B) = 650

n(A∩B) = 170

n(B∩C) = 180

n(C∩A) = 150

n(A∩B∩C) = 50

Therefore;

n(C) = n(A∪B∪C) - (n(A) + n(B) -  n(A∩B) - n(B∩C) - n(C∩A) + n(A∩B∩C))

Substituting the values gives;

n(C) = 1000 - (310 + 650 -  170 - 180 - 150 + 50) = 490

The number of students in the key club, n(C) = 490.

5 0
3 years ago
59.952 nearest tenth
Aleonysh [2.5K]
59.952 in the nearest tenth is 60
5 0
3 years ago
Read 2 more answers
Help me please !!<br> I need this ASAP please helpppp
Kobotan [32]

Answer:

C

Step-by-step explanation:

y=(2x-3)/5

5y=2x-3

(5y+3)/2=x

(5x+3)/2=y

f^{-1}(x)=(5x+3)/2

8 0
3 years ago
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