Answer:
y = -13x + 55
Step-by-step explanation:
perpendicular formula : m1 × m2 = -1
y = -13x + 4
now we take the grafient of the equation which is 13 :
m × 13 = -1
m = -13
so now we hv a new gradient then we can find the equation use the formula y = mx + c :
m = -13 point = ( 4 , 3 )
sub them into the formula,
3 = -13 (4) + c
3 = -52 + c
3 + 52 = c
55 = c
c = 55
now we rewrite again the c and the m to become a complete equation : y = -13x + 55
Solution A1 is correct hope it helpsss
You would do three square in length and 31 in width
Step 1
Find the area of one equilateral triangle
Applying the law of sines
in this problem
a=b=7 cm
C=60 degrees
so
cm²
Step 2
To calculate the area of the hexagon multiply the area of one equilateral triangle by 
![Area Hexagon=6*[49*\frac{\sqrt{3}}{4}] \\ Area Hexagon=73.5*\sqrt{3}](https://tex.z-dn.net/?f=%20Area%20Hexagon%3D6%2A%5B49%2A%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D%5D%20%20%5C%5C%20Area%20Hexagon%3D73.5%2A%5Csqrt%7B3%7D%20%20)
cm²
therefore
the answer is the option
73.5 sqrt 3cm²
The second one, fourth one, and sixth one are true.
Hope this helps!
