division problem
In a division problem, the number being divided into pieces is the dividend. The number by which the dividend is divided is called the divisor. And the answer to the division problem is the quotient.
Answer:
ASA
Step-by-step explanation:
Given:
Two triangles ABC and EDC such that:
AB ⊥ BD and BD ⊥ DE
C is the midpoint of BD.
The two triangles are drawn below.
Since, AB ⊥ BD and BD ⊥ DE
Therefore, the two triangles are right angled triangle. The triangle ABC is right angled at vertex B. The triangle EDC is right angled at vertex D.
Since, point C is the midpoint of the line segment BD.
Therefore, C divides the line segment BD into two equal parts.
So, segment BC ≅ segment CD (Midpoint theorem)
Now, consider the triangles ABC and EDC.
Statements Reason
1. ∠ABC ≅ ∠CDE Right angles are congruent to each other
2. BC ≅ CD Midpoint theorem. C is midpoint of BD
3. ∠ACB ≅ ∠ECD Vertically opposite angles are congruent
Therefore, the two triangles are congruent by ASA postulate.
So, the second option is correct.
Interest = Principle(Rate)(Time)
$84.50 = P(0.0325)(4)
$84.50 = P(0.13)
$84.50/0.13 = P
P = 650
$650 was originally deposited.
Answer:
The coefficient of x becomes 4. Hope it helps you
Step-by-step explanation:
To fund any volume,you multiply the cross sectional are by the depth of the shape