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MrRa [10]
3 years ago
12

What is five sixths of 30

Mathematics
2 answers:
avanturin [10]3 years ago
4 0
30 divided by 6 is 5. 5x5=25 Therefore five sixths of 30 is 25
REY [17]3 years ago
3 0
If you would like to know how much is five sixths of 30, you can calculate this using the following steps:

five sixths of 30 = 5/6 of 30 = 5/6 * 30 = 25

Result: Five sixths of 30 is 25.
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What is the degree Celsius temperature of a person with 95 degree Fahrenheit fever​
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Answer:

35° Celsius

Step-by-step explanation:

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3 years ago
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If 5x – 4 = 31, what is the value of x?​
Lunna [17]

Answer:

x = 5 \frac{2}{5}

Step-by-step explanation:

Hi there!

So, to answer this problem, I'll use the reverse method.

31 - 4 = 27,

So how many times, can 5 go into 27?

The closest factor of 5 to 27 is 25.

5 can go in to 27,  5 times.

Continuing on, there is a 2 left over, so the answer to your question is

x = 5 \frac{2}{5}

5 · 5 \frac{2}{5} - 4 = 31

Let me know if I am incorrect and I will attempt to find the right answer for you.

<em>waffletowne</em>

7 0
3 years ago
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The data set represents a progression of hourly temperature measurements.Use the regression equation to predict the temperature
zimovet [89]
I will attach google sheet that I used to find regression equation.
We can see that linear fit does work, but the polynomial fit is much better.
We can see that R squared for polynomial fit is higher than R squared for the linear fit. This tells us that polynomials fit approximates our dataset better.
This is the polynomial fit equation:
T(h)=20.2-3.6h-0.875h^2
I used h to denote hours. Our prediction of temperature for the sixth hour would be:
T(6)=20.2-3.6(6)-0.875(6)^2=-32.9
Here is a link to the spreadsheet  (<span>https://docs.google.com/spreadsheets/d/17awPz5U8Kr-ZnAAtastV-bnvoKG5zZyL3rRFC9JqVjM/edit?usp=sharing)</span>

4 0
3 years ago
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Step-by-step explanation:

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5 0
2 years ago
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D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
3 years ago
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