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frosja888 [35]
3 years ago
6

Charlie wants to swim across a river that's is 400 meters wide. He begins swimming perpendicular to the shore he from but ends u

p on the opposite side 100 meters down river from where he started due to the current. Carter starts swimming from the same spot as Charlie and ends up 50 meters further down river than Charlie. How much farther did Carter swim? Round your answer to the nearest meter.
Mathematics
1 answer:
nirvana33 [79]3 years ago
4 0
Let's calculate Charlie swimming distance. Assume Charlie swimming distance is D.
D^2 = 400^2 + 100^2 => D = 412 meters

Assume d is Carter's distance.
d^2 = 400^2 + 150^2 => d = 427 meters

Carter swims more than Charlie by:
d - D = 427 - 412 = 15 meters
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Answer please if you can:))
MaRussiya [10]
I can’t see the exact numbers because the pic is blurry but here’s how to solve it.

The three angles in a triangle always add up to 180. So subtract the angle that’s given and you’ll have the sum of the two other angles. Since it’s an equilateral triangle, the other two angles are the same.
So write the equation 2(whatever the angle is) = the number you get when you do 180-the given angle

For example (I’m not sure these numbers are right because the pic is blurry)
2(9x+7)=114
Then you would solve for x and once you get x, plug it into the angle expression 9x+ 7 or whatever to get the angle measure.
5 0
2 years ago
Please help a girl out :)
Vilka [71]

Answer:

1/6

Step-by-step explanation:

I don't know how to use it using a number line sorry

-1/3 - (-1/2)

Two minuses give us a plus

so:

-1/3 + 1/2

make the denominators the same and what you multiply at the bottom you multiply at the top (check online about adding fractions if you don't understand)

so:

-2/6 + 3/6 = 1/6

8 0
3 years ago
Read 2 more answers
Can anyone help me with this?
Vanyuwa [196]

Answer:

-2.5°F

Step-by-step explanation:

-12 - 48 = -60

-60/24 = -2.5°F

7 0
3 years ago
Find two numbers that have a sum of 4 and a product of -5
nekit [7.7K]

Answer:

-1 and 5

Step-by-step explanation:

7 0
3 years ago
Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
(\frac{a}{b})^c=\frac{a^c}{b^c}
and
(a/b)/(c/d)=(ad)/(bc)
and
(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
example: -x^m=-1(x^m) but (-x)^m=(-1)^m(x^m)

so

4.
(\frac{c^{-2}}{2})^{-2}=

\frac{(c^{-2})^{-2}}{2^{-2}}=

\frac{c^4}{\frac{1}{2^2}}=

\frac{c^4}{\frac{1}{4}}=

4c^4



5.

\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=

\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=

\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

\frac{(a^4bc^5)b^3}{(-1)(a^2)}=

\frac{-a^4b^4c^5}{a^2}=

-a^2b^4c^5
3 0
3 years ago
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