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frosja888 [35]
3 years ago
6

Charlie wants to swim across a river that's is 400 meters wide. He begins swimming perpendicular to the shore he from but ends u

p on the opposite side 100 meters down river from where he started due to the current. Carter starts swimming from the same spot as Charlie and ends up 50 meters further down river than Charlie. How much farther did Carter swim? Round your answer to the nearest meter.
Mathematics
1 answer:
nirvana33 [79]3 years ago
4 0
Let's calculate Charlie swimming distance. Assume Charlie swimming distance is D.
D^2 = 400^2 + 100^2 => D = 412 meters

Assume d is Carter's distance.
d^2 = 400^2 + 150^2 => d = 427 meters

Carter swims more than Charlie by:
d - D = 427 - 412 = 15 meters
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in 2017, there were 8950 public parks in the united states. of those parks, 76% provided citizens with restrooms. based on this
pogonyaev

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6802

Step-by-step explanation:

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Hi , step by step please
Zigmanuir [339]

Answer:

Eldest: $335,500   Middle: $182,750   Youngest: $167,750

Step-by-step explanation:

Let's represent the amount of money the youngest sibling received as x.

The amount the eldest received can be represented as: 2x

The amount the middle sibling received can be represented as: x + 15,000

If we combined the amount of money that all of the siblings received, it would be $686,000. We can write this as an equation:

686,000 = 2x + (x + 15,000) + x

Now let's solve for x. First, combine like terms

686,000 = 4x + 15,000

Subtract 15000 from both sides to isolate the 4x

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Divide both sides by 4 to isolate the x

167,750 = x

Now we know that the amount of money the youngest received is $167,750. We can use this amount to figure out how much the other two siblings received.

Eldest: 2 * 167,750 = $335,500

Middle: 167,750 + 15,000 = $182,750

We can check to make sure these answers are correct by adding them all together to make sure that they equal 686,000

167,750 + 335,500 + 182,750 = 686,000

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3 years ago
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Answer:

  4a. ∠V≅∠Y

  4b. TU ≅ WX

  5. No; no applicable postulate

  6. see below

Step-by-step explanation:

<h3>4.</h3>

a. When you use the ASA postulate, you are claiming you have shown two angles and the side between them to be congruent. Here, you're given side TV and angle T are congruent to their counterparts, sides WY and angle W. The angle at the other end of segment TV is angle V. Its counterpart is the other end of segment WY from angle W. In order to use ASA, we must show ...

  ∠V≅∠Y

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b. When you use the SAS postulate, you are claiming you have shown two sides and the angle between them are congruent. The angle T is between sides TV and TU. The angle congruent to that, ∠W, is between sides WY and WX. Then the missing congruence that must be shown is ...

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<h3>5.</h3>

The marked congruences are for two sides and a non-included angle. There is no SSA postulate for proving congruence. (In fact, there are two different possible triangles that have the given dimensions. This can be seen in the fact that the given angle is opposite the shortest of the given sides.)

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<h3>6.</h3>

The first statement/reason is always the list of "given" statements.

1. ∠A≅∠D, AC≅DC . . . . given

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