Answer:
Step-by-step explanation:
Given
Required
Approximate (to the nearest 100th)
This means that, we approximate at the second digit after the decimal.
So:
i.e,
Number = 39.79 [Begin approximation] 949748
The first digit after [Begin approximation] is then approximated using the following rule:
Since 9 falls in category, the number becomes:
![Number = 39.[79+1]](https://tex.z-dn.net/?f=Number%20%3D%2039.%5B79%2B1%5D)
If the line segment point is D(-5, 10) and E(a,b) and the midpoint of the segment is F(13, -2) that mean
DE= 2*DF
You can directly find the distance of AC
Xdf= Xf-Xd= 13 - (-5)= 18
Ydf= Yf - Yd= -2 - 10= -12
Then add the distance of AB( which is 2*AC) to point D
Xe= a = Xd + 2*Xdf
a= -5 +2*18= 31
Ye= b = Yd + 2Yf
b= 10+ 2*-12= -14
<span>absolute difference between a and b:
|b-a|= </span>|-14-31|= 45
Answer:
Step-by-step explanation:
this is a set problem (mathematical set)
30 students played soccer
9 students played cricket and soccer
x students played neither cricket nor soccer
3x students played cricket only.
we can see that in the first set 21 appears and in the middle of the set 9 because it says 30 students played soccer adding x and 3x we have the following formula
30 + x + 3x = 50 where x is equal to 5 then ask us Determine the number of students who played cricket. then the value would be 3x + 9 = (3x5) + 9 = 24
Answer: g(f(x)) = g(x²-7)=x
Step-by-step explanation:
