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goldfiish [28.3K]
2 years ago
12

Answer please if you can:))

Mathematics
1 answer:
MaRussiya [10]2 years ago
5 0
I can’t see the exact numbers because the pic is blurry but here’s how to solve it.

The three angles in a triangle always add up to 180. So subtract the angle that’s given and you’ll have the sum of the two other angles. Since it’s an equilateral triangle, the other two angles are the same.
So write the equation 2(whatever the angle is) = the number you get when you do 180-the given angle

For example (I’m not sure these numbers are right because the pic is blurry)
2(9x+7)=114
Then you would solve for x and once you get x, plug it into the angle expression 9x+ 7 or whatever to get the angle measure.
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ABCD Is a rectangle that represents a park.
Andru [333]

Answer:

Shortest distance from A to C = 102.9005 m.

Step-by-step explanation:

It is given that, ABCD is a rectangular park.

The length of the park is 80 m.

The breadth of the park is 50 m.

The diameter of the circle = 15 m.

We have to calculate the shortest distance from A to C across the park.

The distance AC = \sqrt{50^{2}+80^{2} } = 94.339 m.

As one has to pass only through the lines shown, he cannot pass through the circle.

So, we have to subtract the diameter of 15 m from AC

=> 94.339 m - 15 m = 79.339 m.

One must pass through either half of the circumference of the circle.

Since, diameter of circle = 15 m, its radius(r) = \frac{15}{2} = 7.5 m.

The circumference of the circle = 2×π×r = 47.123 m.

Half of the circumference = \frac{47.123}{2} = 23.5615 m.

Distance from A to C passing through circumference = 79.339 m + 23.5615 m = 102.9005 m.

As we have to calculate the shortest distance from A to C, one cannot pass  from A to C either through B or D,

since the distance ABC or ADC = 50+80 = 130 m.

Therefore, shortest distance from A to C = 102.9005 m.

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Step-by-step explanation:

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Answer:

10.37

Step-by-step explanation:

find the area of the whole rectangle which is 30 then find the area of the circle which is 19.63 then subtract 30-19.63

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