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Fantom [35]
3 years ago
14

How does acceleration due to gravity changes wit depth?

Physics
1 answer:
ivann1987 [24]3 years ago
7 0

Decreases

Explanation:

The acceleration due to gravity on a body decreases with depth.

Acceleration due to gravity is the change in velocity with time of a body as result of the pull of gravity or gravitational force.

  • The acceleration due to gravity tend to pull all bodies to the center of the earth.
  • As body moves away from the center of the earth, the pull becomes very more and acceleration increase.
  • But when a body approaches the center of the earth, the acceleration reduces.
  • At depth, the acceleration due to body of a body begins to decrease.

learn more:

Gravity brainly.com/question/10934170

#learn more brainly.com/question/10934170

#learnwithBrainly

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A baseball is hit so that it travels straight upward after being struck by the bat. A fan observes that it takes 3.00 s for the
Vladimir [108]

Answer:

Initial velocity = 29.43m/s b) Height it reaches = 44.145 m

Explanation:

Using the first equation of motion we have

v=u+at

here

v is the final velocity

u is the initial velocity

a is the acceleration of the object

t is time

When the ball reaches it's highest point it's velocity will become 0 as it will travel no further

Also the acceleration in our case is acceleration due to gravity (-9.8m/s^{2}) as the ball moves in it's influence alone with '-' indicating downward direction

Thus applying the values we get

0=u-(9.81)m/s^{2}\times 3\\\\u=19.43m/s

b)

By 3rd equation of motion we have

v^{2}-u^{2}=2gs

here s is the distance covered

Applying the value of u that we calculated we get

s=\frac{-u^{2}}{2g}\\\\s=\frac{-29.43^{2}}{-2\times 9.81}\\\\s=44.145m

7 0
3 years ago
Which sport requires the least amount of agility? HELLLLPPP
ZanzabumX [31]

Answer:

golf

Explanation:

it's less physical strength in more of you hitting the ball with whatever the stick is called

5 0
3 years ago
John is traveling north at 20 meters/second and his friend Betty is traveling south at 20 meters/second. If north is the positiv
DanielleElmas [232]
John's velocity is 20 m/s north.
Betty's velocity is 20 m/s south.
Their speeds are both 20 m/s.
3 0
3 years ago
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The maximum Compton shift in wavelength occurs when a photon isscattered through 180^\circ .
vlabodo [156]

Answer: 90\°

Explanation:

The Compton Shift \Delta \lambda in wavelength when the photons are scattered is given by the following equation:

\Delta \lambda=\lambda_{c}(1-cos\theta)     (1)

Where:

\lambda_{c}=2.43(10)^{-12} m is a constant whose value is given by \frac{h}{m_{e}c}, being h the Planck constant, m_{e} the mass of the electron and c the speed of light in vacuum.

\theta) the angle between incident phhoton and the scatered photon.

We are told the maximum Compton shift in wavelength occurs when a photon isscattered through 180\°:

\Delta \lambda_{max}=\lambda_{c}(1-cos(180\°))     (2)

\Delta \lambda_{max}=\lambda_{c}(1-(-1))    

\Delta \lambda_{max}=2\lambda_{c}     (3)

Now, let's find the angle that will produce a fourth of this maximum value found in (3):

\frac{1}{4}\Delta \lambda_{max}=\frac{1}{4}2\lambda_{c}(1-cos\theta)      (4)

\frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}(1-cos\theta)      (5)

If we want \frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}, 1-cos\theta   must be equal to 1:

1-cos\theta=1   (6)

Finding \theta:

1-1=cos\theta

0=cos\theta  

\theta=cos^{-1} (0)  

Finally:

\theta=90\°    This is the scattering angle that will produce \frac{1}{4}\Delta \lambda_{max}      

7 0
3 years ago
To determine a waves' frequency, you must know the
kykrilka [37]
B. number of oscillations in a given period of time.
7 0
4 years ago
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