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Natasha2012 [34]
3 years ago
12

A 27N force is applied to a 2.8kg mass on level ground. If a 10N frictional force is present between the surface and the object,

what is the magnitude of the acceleration of the object?
Physics
1 answer:
Degger [83]3 years ago
3 0

Answer:

6.1 m^2

Explanation:

first subtract 10(the friction force) from 27.

acceleration=force/mass

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Oil can be used to reduce friction.
WINSTONCH [101]

Answer:

If you're asking if this is true or false, the answer is true.

Explanation:

7 0
3 years ago
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According to ohms law if you don't change the value of the resistor and you double the voltage in a circuit the amount of curren
padilas [110]

Answer: D (doubled)

According to ohm's law

                      I = V/R ,

                      V = IR ;   R = constant and V is doubled

  From the equation

                      V is directly proportional to the current, and it is given that R is constant ;

                    2V = 2I. R    since R = constant

                      Hence I is doubled.

                     

                   

5 0
4 years ago
A large truck is crossing a bridge 1 mile long. The bridge can only hold 14000 lbs, which is the exact weight of the truck. The
klasskru [66]
Depends on the weight of the bird.
1) Half a mile is about 800m.
2) 14000 lbs = about 6 tones, same like couple 4WD
3) Fuel consumption is about 20L per 100km or 0.2l each 1km or 0.16L within 800m
4) density of fuel is about 70% of density of water so .... weight of 1.6L of fuel burned would be about 1.6*0.7=1.1 kg

So if birds mass would be below 1 kg - the bridge will not collapse. But if it would be a pelican with the mass of 9kg - it would be a drama :)


  
8 0
3 years ago
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A city bus travels along its route from Jackson Street 8 km to Aurora Avenue, where it turns and continues 13 km.
Elina [12.6K]

im a bit confused on what the question is:(

if its just asking for the total number of km traveled it would be 21 km

3 0
3 years ago
A geothermal plant uses geothermal water (yes a liquid) extracted from beneath the Earth using drilling apparatus. The geotherma
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To solve this problem it is necessary to apply the concepts of heat change and thermal efficiency.

The heat rate can be expressed under the function

Q = \dot{m} (h_1-h_2)

Where,

m = Mass

h_i = Enthalpy at each state

Our values are given as,

\dot{m} = 200kg/s

T_H = 200\°C

W = 6000kW

T_{H,2} = 90\°C

T_L = 25\°C

From the tables of Enthalpy of Water at 200°C (Saturated liquid state)

h_1 = 852.4kJ/Kg

At the same time for 80°C

h_2 = 334.9kJ/Kg

Applying the equation of Heat,

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6 0
3 years ago
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