When the difference between one and two numbers is two, the two numbers are -10 and -12.
Given that,
The difference between one and two numbers is two. Twelve more than six times the second is four times the first.
We have to find the number.
We know that,
The system of equation we get
x=y-2 ----->equation(1)
4x=12+6y ----->equation(2)
Substitute for x in the equation(2)
4(y-2)=12+6y
4y-8=12+6y
4y-6y=12+8
-2y=20
y=-10
Substitute y=-10 in equation(1)
x=-10-2
x=-12
Therefore, The two numbers area -10 and -12 when the difference between one and two numbers is two.
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Here are three ways where There could be equal rows
3*12=36
4*9=36
6*6=36
Answer: - 0.027
Step-by-step explanation:
Win = any even number between (0 - 36)
Therefore,
Lose = any odd number between 0 —36 including 0
Assume Bet amount = $1
Expected value is calculate by summing all possible outcomes by their respective probabilities.
Expected value = [(p(winning) × net win value) + (p(losing +net loss value]
P(winning) = p(even) = 18/37
P(losing) = p(odd) +p(0) = 19/37
Net win value = $2
Net loss value = $-1
Expected value = [(18/37) × ($1) + (19/37) × (-$1)]
Expected value = 0.48648648 - 0.51351351
Expected value = - 0.027
