Answer:
<h3>The possibilities of length and width of the rectangle are </h3><h3>x=1, y=0.24;</h3><h3>x=0.5, y=0.48;</h3><h3>x=0.25, y=0.96;</h3><h3>x=2, y=0.12</h3>
Step-by-step explanation:
Given that the area is 0.24 square meter
The area of a rectangle is given by
square units
Let x be the length and y be the width.
Since the area is 0.24 square meter, we have the equation:
, with x and y measures in meters
If we want to know some possibilities of x and y, we can assume a value for one of them, and then calculate the other one using the equation.
Now choosing some values for "x", we have:
Put x = 1
![1\times y = 0.24](https://tex.z-dn.net/?f=1%5Ctimes%20y%20%3D%200.24)
∴ y = 0.24
Now put x = 0.5 we get
∴ y = 0.48
Put x = 0.25
∴ y = 0.96
Put x = 2
![2\times y = 0.24](https://tex.z-dn.net/?f=2%5Ctimes%20y%20%3D%200.24)
∴ y = 0.12
Answer:
n = 6![\sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)
Step-by-step explanation:
Using the sine ratio in the right triangle and the exact value
sin30° =
, then
sin30° =
=
=
( cross- multiply )
2n = 12
( divide both sides by 2 )
n = 6![\sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)
I think the answer is B.
Hope this helps.
Answer:
![16\sqrt{17}](https://tex.z-dn.net/?f=16%5Csqrt%7B17%7D)
Step-by-step explanation:
The perimeter is two times width plus two times length:
![2\sqrt{17} + 2\cdot 7\sqrt{17} = 2\sqrt{17} + 14\sqrt{17} = 16\sqrt{17}](https://tex.z-dn.net/?f=2%5Csqrt%7B17%7D%20%2B%202%5Ccdot%207%5Csqrt%7B17%7D%20%3D%202%5Csqrt%7B17%7D%20%2B%2014%5Csqrt%7B17%7D%20%3D%2016%5Csqrt%7B17%7D)
There is no way to simplify further.