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brilliants [131]
3 years ago
8

5. Sam wrote the expression below.

Mathematics
1 answer:
Fed [463]3 years ago
6 0

Answer:

see below

Step-by-step explanation:

10 + 15k

Factor out the greatest common factor 5

5( 2+3k)

Rewriting

5(3k+2)

Rami is correct if a=2 then his expression is 5(3k+2)

Kenneth

yk+6+8k+4

Add the terms together

k(y+8) + 10

If y =7 then Kenneth is correct otherwise he is incorrect

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A dog is moving at a constant speed of 8 m/s. what is the dog’s acceleration
ozzi

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: Acceleration_{dog} = 0

____________________________________

\large \tt Solution  \: :

A dog is moving at a constant speed of 8 m/s, that concludes that there's no change in its speed with respect to time.

And Acceleration is define as rate of change in velocity, but since velocity/speed is constant. change in velocity = 0

Henceforth, Acceleration of dog is 0 as well.

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

4 0
2 years ago
Read 2 more answers
A basketball player has made 6060​% of his foul shots during the season. Assume the shots are independent. ​
motikmotik

Answer:

a) 2.5 shots

b) 59.4 shots

c) 4.87 shots

Step-by-step explanation:

Probability of making the shot = 0.6

Probability of missing the shot = 0.4

a) The expected number of shots until the player misses is given by:

E(X) = \frac{1}{P(X)}=\frac{1}{0.4}  \\E(X) = 2.5\ shots

The expected number of shots until the first miss is 2.5

b) The expected number of shots made in 99 attempts is:

E=99*0.6\\E=59.4\ shots

He is expected to make 59.4 shots

c) Let "p" be the proportion shots that the player make, the standard deviation for n = 99 shots is:

s=\sqrt{n*p*(1-p)}\\ s= 4.87\ shots

The standard deviation is 4.87 shots.

7 0
3 years ago
PLEASE HELP AND FAST!!!
lesya692 [45]
The answer is the top one.
8 0
3 years ago
The population of Henderson City was 3,381,000 in 1994, and is growing at an annual rate 1.8%
liq [111]
<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>

Step-by-step explanation:

   Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.

   From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by \frac{100+1.8}{100} = \frac{101.8}{100}.

   So, the population in the year t can be given by P(t)=3,381,000\textrm{x}(\frac{101.8}{100})^{(t-1994)}

   Population in the year 2000 = 3,381,000\textrm{x}(\frac{101.8}{100})^{6}=3,762,979.38

Population in year 2000 = 3,762,979

   Let us assume population doubles by year y.

2\textrm{x}(3,381,000)=(3,381,000)\textrm{x}(\frac{101.8}{100})^{(y-1994)}

log_{10}2=(y-1994)log_{10}(\frac{101.8}{100})

y-1994=\frac{log_{10}2}{log_{10}1.018}=38.8537

y≈2033

∴ By 2033, the population doubles.

4 0
4 years ago
Refer to the equation 2x − 6y = 12 Create a table of values for at least 4 points. Show your work
natka813 [3]

Answer: The table and figure are given below,

Solution:

The given equation is 2x-6y=12.

put x=0 in the equation.

2(0)-6y=12

-6y=12

y=-2

Similarly find the values of y at different values of x. The values are shown in the table.

From table it is notices that the value of y=-2 for x=0, y=-1 for x=3, y==-3 for x=-3, y=0 for x=6.

Plot these points in the coordinate plane and joint them by a straight line.

The gra his shown in below figure.

6 0
3 years ago
Read 2 more answers
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