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Delicious77 [7]
4 years ago
6

Find the pattern in the Fibonacci sequence and identify the next two terms.

Mathematics
1 answer:
klasskru [66]4 years ago
5 0

For the Fibonacci sequence you add the two previous numbers. You always start with 0, 1 and you add 0 and 1 which makes 1 then 1 + 1 makes two and so on. The next number in the sequence would be 34 + 55, meaning 89, and after that would be 55 + 89, or 144.

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Gina takes classes at both Westside Community College and Pinewood Community College. At Westside, class fees are $98 per credit
Kipish [7]

Answer: second option.

Step-by-step explanation:

Let be "w" the credit hours at Westside Gina is taking.

You know that class fees are $98 per credit hour at Westside, then the expression for the dollar amount she paid for her class fees at Westside is:

98w

Since she is taking a combined total of 13 credit hours at the two schools, the credit hours at Pinewood Gina is taking can be represented by this expression:

13-w

You know that class fees are $115 per credit hour at Pinewood, then the dollar amount she paid for her class fees at Pinewood can be expressed as:

115(13-w)

Therefore, the expression for the combined total dollar amount she paid for her class fees is:

total\ paid=98w+115(13-w)\\\\total\ paid= -17w + 1495

6 0
3 years ago
Read 2 more answers
Someone please solve all equations
Tamiku [17]

17. (a) The formula with CP subject is CP=\frac{SP}{1.1}

(b) The Cost Price of item without GST is $59.50

(c) The GST of item is $5.95

Step-by-step explanation:

Given formula is;

SP = 1.1 * CP

SP = Selling price

CP = Cost price

(a) Rearrange the formula to make CP the subject;

SP = 1.1 * CP

Dividing both sides by 1.1

\frac{SP}{1.1}=\frac{1.1*CP}{1.1}\\\\\frac{SP}{1.1}=CP\\\\CP=\frac{SP}{1.1}

The formula with CP subject is CP=\frac{SP}{1.1}

(b) Use your formula from (a) to find the Cost Price of an item without GST if the selling price is $65.45

SP = $65.45

CP=\frac{65.45}{1.1}\\\\CP=\$59.50

The Cost Price of item without GST is $59.50

(c) Calculate the amount of GST on an item whose selling price is $65.45.

GST = 10% of CP

GST = \frac{10}{100}*CP

GST = 0.1CP

From part (b)

CP = $59.50

GST = 0.1 * 59.50

GST = $5.95

The GST of item is $5.95

Keywords: percentage, multiplication

Learn more about multiplication at:

  • brainly.com/question/10764770
  • brainly.com/question/1087090

#LearnwithBrainly

3 0
3 years ago
If the line passing through the points (a, 1) and (−17, 8) is parallel to the line passing through the points (0, 5) and (a + 2,
stellarik [79]
Parallel line means the same slope
(8-1)/(-17-a)=(1-5)/(a+2)
so a is 18
4 0
3 years ago
Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-ma
pickupchik [31]

Answer:

Answer explained below

Step-by-step explanation:

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-mails containing the same virus, after which the virus disables itself on that machine. (1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds. (2) Solve the recurrence relation. (3) How many e-mails are sent at the end of 20 seconds

1.START T=0.....

1000 EMAILS SENT AND RECEIVED BY 1000 M/CS.

T=1.....

EACH OF THE M/C SENDS 10 NEW MAILS ....

.................................

LET M[N] BE THE NUMBER OF MAILS SENT OUT AFTER N SECONDS.

SO , EACH OF THESE M/CS WILL SEND 10 MAILS IN NEXT 1 SECOND.

HENCE NUMBER OF MAILS SENT IN N+1 SECONDS=M[N+1]=

M[N+1]=10*M[N].......................1

THIS IS THE RECURRENCE RELATION.....

2.SOLUTION .....

M[N+1]=10M[N]=10*10M[N-1]=10*10*10M[N-2]=........

M(N+1)=[10^1][M(N)]=[10^2][M(N-1)]=[10^3][M(N-2)]=..........=[10^N][M(1)]=[10^(N+1)][M(0)]

M[N+1]=[10^(N+1)][1000]=[10^(N+1)][10^3]=[10^(N+4)]......................................2

THIS IS THE NUMBER OF MAILS SENT AFTER N+1 SECONDS .....OR ....

M[N]=[10^(N+3)].............................................3

..................IS THE SOLUTION FOR NUMBER OF MAILS SENT AFTER N SECONDS.....

3.AFTER N=20 SECONDS , THE ANSWER IS ....

M[20]=10^(20+3)=10^23

8 0
3 years ago
Read 2 more answers
Please help i need it !!!
Sedbober [7]

Answer:

x=7

Step-by-step explanation:

3 0
3 years ago
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