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velikii [3]
3 years ago
13

In which of the following data sets is the mean equal to the mode?

Mathematics
1 answer:
vazorg [7]3 years ago
5 0

Answer:

The second data set.

Step-by-step explanation:

In Data set 1, mean is 4.8, the mode is 4.

In Data set 2, the mean is 5 and the mode is 5.

In Data set 3, the mean is 4.6 and the mode is 3.

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Which is the value of this expression when X=-2
e-lub [12.9K]
A) x^2 +x -30 = 0 is factored by looking for two factors of 30 that differ by 1. We know ...  30 = 1*30 = 2*15 = 3*10 = 5*6The last two factors differ by 1, so we can factor the trinomial as  (x +6)(x -5) = 0
b) The solutions are found by finding values of x that make these factors zero. The only way the product will be zero is if one or more of the factors is zero.  x + 6 = 0  x = -6 . . . . . subtract 6
  x - 5 = 0  x = 5 . . . . . add 5
The solutions are x = -6 or x = 5These are the values of x that will satisfy the equation (make it true). What they mean depends on the meaning of the variable and the situation the equation is a model of.
6 0
3 years ago
Which of the following statement(s) describes the rate of change of f over the interval 1.5 ≤ x ≤ 3? Select all that apply.
Vesnalui [34]

2 Answers: Choice B and Choice C

The rate of change is 2.

The rate of change is constant.

======================================================

Explanation:

The first point on the left is when x = 1.5 and it has a height of y = 1

The point (1.5, 1) is on the line.

So is the point (3,4) for similar reasoning.

Compute the slope between those points

m = (y2-y1)/(x2-x1)

m = (4-1)/(3-1.5)

m = 3/(1.5)

m = 2

The slope is 2, which is the same as saying the rate of change is 2. This only applies when x > 1 of which the interval 1.5 ≤ x ≤ 3  is a part of.

Since the slope stays at 2 on the interval 1.5 ≤ x ≤ 3, this means we consider the slope to be constant. If the curve bended at all on this interval, then it wouldn't be a constant slope.

6 0
2 years ago
Write an equation in​ point-slope form of the line that passes through the given​ points, then write the equation in​ slope-inte
frosja888 [35]

As we go from (-6,6) to (9,1), x increases by 15 and y decreases by 5.  Thus, the slope of this line is m = rise / run = -5/15, or m = -1/3.

Point-slope form:  y-6 = (-1/3)(x+6), using data from (-6,6).  

Slope-intercept form:  starting with y = mx + b, substit. -6 for x, 6 for y and -1/3 for m:

6 = (-1/3)(-6) + b, or

6 = 2 + b.  Then b = 4, and the equation in slope-intercept form is

y = (-1/3)x + 4.

8 0
3 years ago
How many days in the month
iren2701 [21]

January : 31 days.

February : February is the second and shortest month of the year in the Julian and Gregorian calendar with 28 days in common years and 29 days in leap years, with the quadrennial 29th day being called the leap day. It is the first of five months to have a length of less than 31 days, and the only month to have less than 30 days

March : 31 days.

April : 30 days.

May : 31 days.

June : 30 days.

July : 31 days.

August : 31 days.

Septembers : 30 days.

October : 31 days.

November : 30 days.

December : 31 days.



Hope this helps!

7 0
3 years ago
If LP = 15 and PR = 9, find LR. Explain.
Rudiy27

Answer:

24

Step-by-step explanation:

LP = 15 on one side

LR= 9 on the other side

____________________|____________|

 P                                      L                            R

add them and PR is 24

15+9= 24

5 0
3 years ago
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