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velikii [3]
3 years ago
13

In which of the following data sets is the mean equal to the mode?

Mathematics
1 answer:
vazorg [7]3 years ago
5 0

Answer:

The second data set.

Step-by-step explanation:

In Data set 1, mean is 4.8, the mode is 4.

In Data set 2, the mean is 5 and the mode is 5.

In Data set 3, the mean is 4.6 and the mode is 3.

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Reflect the given triangle over<br> the y-axis.<br> 3 6 31<br> -3 3 3
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Answer:(-3,6)(-31,-3)(-3,3)

Step-by-step explanation:

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3 years ago
The city of Madison regularly checks the quality of water at swimming beaches located on area lakes. Fifteen times the concentra
Maksim231197 [3]

Answer:

The sample standard deviation is 393.99

Step-by-step explanation:

The standard deviation of a sample can be calculated using the following formula:

s=\sqrt[ ]{\frac{1}{N-1} \sum_{i=1}^{N}(x_{i}-{\displaystyle \textstyle {\bar {x}}}) ^{2} }

Where:

s= Sample standart deviation

N= Number of observations in the sample

{\displaystyle \textstyle {\bar {x}}}= Mean value of the sample

and \sum_{i=1}^{N}(x_{i}-{\displaystyle \textstyle {\bar {x}}}) ^{2} } simbolizes the addition of the square of the difference between each observation and the mean value of the sample.

Let's start calculating the mean value:

\bar {x}=\frac{1}{N}  \sum_{i=1}^{N}x_{i}

\bar {x}=\frac{1}{15}*(180+1600+90+140+50+260+400+90+380+110+10+60+20+340+80)

\bar {x}=\frac{1}{15}*(3810)

\bar {x}=254

Now, let's calculate the summation:

\sum_{i=1}^{N}(x_{i}-\bar {x}) ^{2} }=(180-254)^2+(1600-254)^2+(90-254)^2+...+(80-254)^2

\sum_{i=1}^{N}(x_{i}-\bar {x}) ^{2} }=2173160

So, now we can calculate the standart deviation:

s=\sqrt[ ]{\frac{1}{N-1} \sum_{i=1}^{N}(x_{i}-{\displaystyle \textstyle {\bar {x}}}) ^{2} }

s=\sqrt[ ]{\frac{1}{15-1}*(2173160)}

s=\sqrt[ ]{\frac{2173160}{14}}

s=393.99

The sample standard deviation is 393.99

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3 years ago
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Answer:

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Answer:

no it is not the same because you get different answers

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3 years ago
What is the answer to this
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The answer is 49.5 for the variable c
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