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oee [108]
3 years ago
6

Total solar eclipses occur on a regular and predictable basis. One that could be viewed in parts of the United States occurred o

n March 7, 1970. The saros cycle is a period of 18 years, 11 1 3 days, and solar eclipses occur according to this cycle. For the purposes of this exercise, we ignore leap years and assume that a year is exactly 365 days. Because the saros cycle is not a whole number of days, but instead is one-third of a day longer than a day, at the end of the saros cycle, Earth will have rotated one-third revolution beyond its location at the beginning of the cycle. Thus, if a solar eclipse is viewable at a certain location, the next solar eclipse will not be. How long after March 7, 1970, will a solar eclipse again be viewable from the United States?
Mathematics
1 answer:
Ivenika [448]3 years ago
8 0

Answer:

Step-by-step explanation:

The previous solar eclipse occured on March 7 , 1970 .

saros cycle has duration of 18 years , 11 + 1/3 days

So the earth goes 1 / 3 of its daily rotation beyond its previous location in the next solar eclipse on the earth . In order that we get solar eclipse on the same point on the earth , we shall have to wait for third solar eclipse

So total period of wait = 18 x 3 years + 11 x 3 + 1 = 54 years and 34 days

Date of next solar eclipse on the same spot = 1970 + 54 = 2024

7 th March + 34 days = April 10

likely date = April 10 , 2024 .

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Farmer Jan is a vegetable farmer who divides his field between broccoli crops and spinach crops. Last year, he grew 6 tons of br
ankoles [38]

Answer:

There is no unique solution to this problem.

There are infinitely many solutions to this problem.

Step-by-step explanation:

Let B denotes broccoli crop

Let S denotes spinach crop

Last year, he grew 6 tons of broccoli per acre and 9 tons of spinach per acre, for a total of 93 tons of vegetables.

Mathematically,

6B + 9S = 93        eq. 1

This year, he grew 2 tons of broccoli per acre and 3 tons of spinach per acre, for a total of 31 tons of vegetables.

Mathematically,

2B + 3S = 31

2B = 31 -  3S

B = (31 -  3S)/2      eq. 2

Substitute eq. 2 into eq. 1

6B + 9S = 93

6[(31 -  3S)/2] + 9S = 93

3(31 -  3S) + 9S = 93

93 - 9S + 9S = 93

- 9S + 9S = 93 - 93

0 = 0

Therefore, there is no unique solution to this problem.

Which means that there are infinitely many solutions to this problem.

5 0
3 years ago
The point c(-3,-2)is translated 1 unit left and 2 units up.what are the coordinates of the resulting point,c
yarga [219]

translation makes this coordinate -4,0

7 0
3 years ago
Y and x have a proportional relationship, and y = 15 when x = 3. What is the value of x when y = 4?
Ksju [112]
In a proportional relationship, x and y will increase at the same rate. In order to find the value of x when y=4, we first have to find the ratio of x:y. We can do this by creating a fraction. After we know the ratio, simply replace the y value with 4 and solve for x. Here's the math:

y=15 when x=3       given values

y/x = 15/3 = 5          ratio of y to x

y=5x                        equation representing the proportional relationship 

4=5x                        replace y with 4

4/5=x                       divide both sides by 5 to isolate x

Answer: The value of x=4/5 when y=4.

Hope this helps!


6 0
3 years ago
Write the explicit formula for this geometric sequence.
Naily [24]

The explicit formula for this  geometric sequence 81, 27, 9, 3, … is aₙ = 81(1/3)ⁿ⁻¹. It has common ratio of 1/3 and first term of 81.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

A geometric sequence is in the form aₙ = ar⁽ⁿ⁻¹⁾, where a is the first term and r is the common ratio.

The geometric sequence 81, 27, 9, 3, … has common ratio:

r = 27/81 = 1/3

The explicit formula for this  geometric sequence 81, 27, 9, 3, … is aₙ = 81(1/3)ⁿ⁻¹. It has common ratio of 1/3 and first term of 81.

Find out more on equation at: brainly.com/question/2972832

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7 0
2 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
Len [333]

Answer:

In the operation, simplify

9-a² = (3-a)(3+a)

Factorize

4a²-4a-24-------------------divide each term by 4

a²-a-6-------------------------factorize

a²-3a+2a-6

a(a-3)+2(a-3)

(a+2)(a-3)

Factorize

a²-6a+9

a²-3a-3a+9

a(a-3)-3(a-3)

(a-3)(a-3)

Rewrite operation as

\frac{8}{(3-a)(3+a)} /\frac{(a+2)(a-3)}{(a-3)(a-3)}

Multiply by the recipricol

\frac{8}{(3-a)(3+a)} *\frac{(a-3)(a-3)}{(a+2)(a-3)}

cancel the similar terms

\frac{8}{(3-a)(3+a)} *\frac{(a-3)}{(a+2)}

6 0
3 years ago
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