Answer:
There is no unique solution to this problem.
There are infinitely many solutions to this problem.
Step-by-step explanation:
Let B denotes broccoli crop
Let S denotes spinach crop
Last year, he grew 6 tons of broccoli per acre and 9 tons of spinach per acre, for a total of 93 tons of vegetables.
Mathematically,
6B + 9S = 93 eq. 1
This year, he grew 2 tons of broccoli per acre and 3 tons of spinach per acre, for a total of 31 tons of vegetables.
Mathematically,
2B + 3S = 31
2B = 31 - 3S
B = (31 - 3S)/2 eq. 2
Substitute eq. 2 into eq. 1
6B + 9S = 93
6[(31 - 3S)/2] + 9S = 93
3(31 - 3S) + 9S = 93
93 - 9S + 9S = 93
- 9S + 9S = 93 - 93
0 = 0
Therefore, there is no unique solution to this problem.
Which means that there are infinitely many solutions to this problem.
translation makes this coordinate -4,0
In a proportional relationship, x and y will increase at the same rate. In order to find the value of x when y=4, we first have to find the ratio of x:y. We can do this by creating a fraction. After we know the ratio, simply replace the y value with 4 and solve for x. Here's the math:
y=15 when x=3 given values
y/x = 15/3 = 5 ratio of y to x
y=5x equation representing the proportional relationship
4=5x replace y with 4
4/5=x divide both sides by 5 to isolate x
Answer: The value of x=4/5 when y=4.
Hope this helps!
The explicit formula for this geometric sequence 81, 27, 9, 3, … is aₙ = 81(1/3)ⁿ⁻¹. It has common ratio of 1/3 and first term of 81.
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
A geometric sequence is in the form aₙ = ar⁽ⁿ⁻¹⁾, where a is the first term and r is the common ratio.
The geometric sequence 81, 27, 9, 3, … has common ratio:
r = 27/81 = 1/3
The explicit formula for this geometric sequence 81, 27, 9, 3, … is aₙ = 81(1/3)ⁿ⁻¹. It has common ratio of 1/3 and first term of 81.
Find out more on equation at: brainly.com/question/2972832
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Answer:
In the operation, simplify
9-a² = (3-a)(3+a)
Factorize
4a²-4a-24-------------------divide each term by 4
a²-a-6-------------------------factorize
a²-3a+2a-6
a(a-3)+2(a-3)
(a+2)(a-3)
Factorize
a²-6a+9
a²-3a-3a+9
a(a-3)-3(a-3)
(a-3)(a-3)
Rewrite operation as

Multiply by the recipricol

cancel the similar terms
