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Alla [95]
3 years ago
12

A grocery store produce manager is told by a wholesaler that the apples in a large shipment have a mean weight of 6 ounces and a

standard deviation of 1.4 ounces. The manager is going to randomly select 49 apples. Suppose the manager is willing to risk a 10% chance of returning the shipment even if the wholesaler's claim is true. Let W be the mean weight of the sample below which the shipment will be returned. Find the value of W.
Mathematics
1 answer:
Andru [333]3 years ago
7 0

Answer:

W= 5.744

Step-by-step explanation:

given that a grocery store produce manager is told by a wholesaler that the apples in a large shipment have a mean weight of 6 ounces and a standard deviation of 1.4 ounces

Sample size n= 49

Margin of error = 0.10 (10% risk )

Let us assume X no of apples having mean weight of 6 oz is N(6,1.4)

Then sample mean will be normal with (6, 1.4/7) = (6,0.2)

(Because sample mean follows normal with std error as std dev /sqrt of sample size)

Now required probability <0.10

i.e.P(\bar X

Since x bar is normal we find z score for

P(Z

From std normal distribution table we find that z = 1.28

Corresponding X score =

W= 6-0.2*1.28\\W= 6-0.256 = 5.744

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1. If f(x) = 4x — 7 and , find each value:<br> a. f(3)<br> b. f(0)
kobusy [5.1K]

Answer:

f(3)=5

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Step-by-step explanation:

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3 years ago
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3. Given AB with coordinates A(-4,5) and B(12,13). Find the horizontal distance and the vertical
SCORPION-xisa [38]

The required distance would be 17.88 units coordinates A(-4,5) and B(12,13) and the horizontal distance is 16 units and the vertical distance is 8 units from A to B which are determined by the graphing method.

<h3>What is the distance between two points?</h3>

The distance between two points is defined as the length of the line segment between two places representing their distance.

Given AB with coordinates A(-4,5) and B(12,13).

The formula of the distance between two points is A(x₁, y₁) and B(x₂, y₂) is given by: d (A, B) = √ (x₂ – x₁)² + (y₂ – y₁) ².

x₁ = -4, y₁ = 5

x₂ = 12, y₂ = 13

distance = √ (12 – (-4))² + (13 – 5)²

distance = √ (12 + 4)² + (8)²

distance = √ (16)² + (8)²

distance = √ (256 + 64)

distance = √320

distance = 17.88 units

The horizontal distance is 16 units and the vertical distance is 8 units from A to B which are determined by the graphing method.

Learn more about the distance between two points here:

brainly.com/question/15958176

#SPJ1

6 0
1 year ago
Please help with this question
12345 [234]
A^2 + b^2 = c^2
3^2 + 4^2 = c^2
9 + 16 = c^2
25 = c^2
5 = c
5 0
3 years ago
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