The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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Answer:
Step-by-step explanation:
2nd one
Answer:
3 minutes and 30 seconds
Step-by-step explanation:
7-5 = 2
3/2 = 1.5 gallons that empty per each minute
1.5 times 3 (minutes) = 4.5 gallons emptied
Remaining gallons to empty = 0.5
0.5 gallons to empty will take 30 seconds
I hope this helps :)
Answer:
7.1
Step-by-step explanation:
328 23 = 14.2608695652
14.2608695652 = 142.608695652 to the nearest tenth
14.2608695652 = 14.26 to the nearest hundredth
14.2608695652 = 14.261 to the nearest thousandth
= 0 to the nearest tenth
= 0 to the nearest hundredth
= 0 to the nearest thousandth
Other Divisions Math homework are
328 divide by half plus 20
Homework answers: (328/2) + 20 = 184
328 divide by half plus 40
Homework answers: (328/2) + 40 = 204
328/23 divided by 2
Answer: (328/23) ÷ 2 = 7.13043478261
