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3 years ago

Can someone help me with this!

Mathematics

1 answer:

Doss [256]3 years ago

3 0

Answer:

Please read the answers below.

Step-by-step explanation:

Let's recall that in a square all its sides are equal length and all the four internal angles measure 90 °

5. If LN = 46, then we have:

OM = 46 (Same length than LN)

PN = LN/2 = 46/2 = 23

ON = √LN²/2 = √ 46²/2 = √ 2,116/2 = √ 1,058 = 32.53 (Rounding to two decimal places)

MN = ON = 32.53

6. m ∠EFG = 90°

m ∠GDH = ∠GDH/2 = 90/2 = 45°

m ∠FEG = ∠DEF/2 = 90/2 = 45°

m ∠DHG = 180 - (∠GDH + ∠DGH) = 180 - (45 + 45)= 180 - 90 = 90°

7. Solve for x

6x - 21 = ∠PQR/2

6x - 21 = 90/2

6x - 21 = 45

6x = 45 +21

6x = 66

x = 11

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MAVERICK [17]

Answer:

no solutions.

Step-by-step explanation:

8x + 14 -4x = 9+4x -5

8x-4x -4x = 9-5-14

0x = -10

anything multiplied by 0 is 0, so it's impossible to get -10 by multiplying by 0

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2 years ago

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babunello [35]

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Step-by-step explanation:

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2 years ago

Which expressions are equivalent to -6 +49 + (-69) ?

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3 years ago

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

$lw+2lh+2wh = 64$

If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

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3 years ago

What is the slope of the line through (-9,6) and (-3, 9)?

Artyom0805 [142]

To find slope, y2-y1/x2-x1
9-6/-3-(-9)=
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Y=1/2x.

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3 years ago