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Blababa [14]
3 years ago
8

Need help with this as soon as possible

Mathematics
2 answers:
andrey2020 [161]3 years ago
4 0

Answer:

6 + 5\sqrt{5}

irrational

cannot

does not

Step-by-step explanation:

5\sqrt{5} + 2\sqrt{9} =

= 5\sqrt{5} + 2 \times 3

= 5\sqrt{5} + 6

= 6 + 5\sqrt{5}

Lemur [1.5K]3 years ago
4 0

Answer:

See below.

Step-by-step explanation:

First, find the sum:

5\sqrt{5}+2\sqrt{9}=5\sqrt{5}+2(3)=5\sqrt{5} +6

As long as part of the equation is irrational, the entire answer will also be irrational. Thus:

The result is irrational because it cannot be written [as] the ratio of two integers and its decimal expansion does not terminate or repeat.

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Want Brainliest? Get this correct Which of the following is the quotient of the rational expressions shown below? Make sure your
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B.

Step-by-step explanation:

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4 0
4 years ago
I need help on both these answer pls someone
Strike441 [17]

Answer:

1) 3(12-1)

2) 33

Step-by-step explanation:

times means multiplication and difference of means subtraction

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6 0
3 years ago
URGENT!! The difference between the roots of the quadratic equation x2−12x+q=0 is 2. Find q
Sedaia [141]

Answer:

q=35

Step-by-step explanation:

x2 - 12x + q = 0

Let the two roots be r and r+2.

Factor the quadratic expression:

(x - r)[x - (r + 2)] = 0

Expand, simplify, group like terms, and get

x2 - 2(r + 1)x + r(r + 2) = 0

Compare to

x2 - 12x + q = 0

and set equal the coefficients of like terms:

Coefficient of x:

-2(r + 1) = -12 ⇒ r + 1 = 6 ⇒ r = 5

(Then the other root is r + 2 = 5 + 2 = 7)

Constant term:

r(r + 2) = q ⇒ 5(5 + 2) = q

q = 35

Test the solution:

(x - 5)(x - 7) = x2 - 12x + 35

With two roots differing by 2, you get an equation of the form

x2 - 12x + q = 0

with q = 35.

3 0
3 years ago
Read 2 more answers
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