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Anni [7]
3 years ago
15

What is the value of y in the equation, 5x+2y=20, when x=0.3

Mathematics
1 answer:
gregori [183]3 years ago
4 0

Answer:

y = -5/2x + 10

Step-by-step explanation:

Step one: Add -5x to both sides.

5x + 2y + -5x = 20 + -5x

2y = -5x + 20

Step two: Divide both sides by two.

2y/2 = -5x + 20/ 2

y = -5/2x + 10

Hope my answer help.

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4535 divided by 83 = R =
Leto [7]

Answer:

54 R 53

54 53/83

Step-by-step explanation:

4535 divided by 83 equals

54 with a remainder of 53

8 0
3 years ago
Find the area of the triangle when b=8 and h=14
babunello [35]

Answer:

56 square units

Step-by-step explanation:

The formula for the area of a triangle of base b and height h is:

A = (1/2)(b)(h)

Here, that area is   A = (1/2)(8)(14) = 56 square units

4 0
3 years ago
A soccer ball made of leather 1/81/8 in thick has an inner diameter of 8.58.5 in . Use the formula V=(4/3)πr3V=(4/3)πr3 to calcu
Sphinxa [80]
1/8 inch thick
inner diameter of 8.5

volume shell=volume total-volume shell


1/8=0.125

diameter/2=radius
radius inner=8.5/2=4.25
radiustotal=inner+outer=4.25+0.125=4.375


so

Vouter-Vinner=(4/3)pi4.375³-(4/3)pi4.25³
Vshell=(4/3)(pi)(4.375³-4.25)
Vshell=(4/3)(pi)(83.740234375-76.765625)
Vshell=(4/3)(pi)(6.974609375)
Vshell=9.299479166666666666666pi cubic inches
Vshell≈16.433536180619 cubic inches
6 0
3 years ago
Read 2 more answers
The heights of North American women are normally distributed with a mean of 64 inches and a standard deviation of 2inches.a. Wha
Charra [1.4K]

Answer:

a)P(X>66)=P(Z>1)=1-P(Z

b)P(\bar X >66)=P(Z>2)=1-P(Z

c) P(\bar X >66)=P(Z>10)=1-P(Z

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

2) Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(64,2)  

Where \mu=64 and \sigma=2

We are interested on this probability

P(X>66)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-\mu}{\sigma})=P(Z>\frac{66-64}{2})=P(Z>1)

And we can find this probability on this way:

P(Z>1)=1-P(Z

3) Part b

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

P(\bar X >66)=P(Z>\frac{66-64}{\frac{2}{\sqrt{4}}}=2)

And using a calculator, excel or the normal standard table we have that:

P(Z>2)=1-P(Z

4) Part c

P(\bar X >66)=P(Z>\frac{66-64}{\frac{2}{\sqrt{100}}}=10)

And using a calculator, excel or the normal standard table we have that:

P(Z>10)=1-P(Z

3 0
3 years ago
Evaluate the double integral. . ∫∫ y sqrt(x^2-y^2) dA, R={(x,y)|0≤y≤x, 0≤x≤1}. R. . Please explain
polet [3.4K]
First we will evaluate: ( substitution: u = x² - y²,  du = - 2 y dy )
\int\limits^x_0 {y \sqrt{ x^{2} - y^{2} } } \, dy= \\   \frac{-1}{2} \int\limits^x_0 { u^{1/2} } \, du  =
=\frac{-1}{3} \sqrt{ (x^{2} - y^{2} ) ^{3} } ( than plug in x and 0 )
=- \frac{1}{3} (  \sqrt{( x^{2} - x^{2}) ^{3}  }  -  \sqrt{ (x^{2} -0 ^{2} ) ^{3} } =
= 1/3 x³ ( then another integration )
1/3\int\limits^1_0 { x^{3} } \, dx = 1/3 (  x^{4}/4)}= 1/3 ( 1 ^{4}/4 - 0^{4} /4 )
= 1/3 * 1/4 = 1/12
4 0
3 years ago
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