1. You need to multiply the denominator by something that will make the content of the radical be a square—so that when you take the square root, you get something rational. Easiest and best is to multiply by √6. Of course, you must multiply the numerator by the same thing. Then simplify.

2. Identify the squares under the radical and remove them.

Answer:
The correct option is C
Step-by-step explanation:
if f(x)= x3 + x2 - 20x
Replace f(x) by y
y = x3 + x2 - 20x
0 =x3 + x2 - 20x
x3 + x2 - 20x = 0
Take out x as a common:
x(x2+x-20)=0
Find factors of x2+x+20.
x(x^2+4x-5x-20) = 0
x{x(x+4)-5(x+4)}=0
x(x+4)(x-5)=0
Set x= 0
x=0 , x+4=0 , x-5 =0
x=0, x=0-4 , x=0+5
x=0, x= -4, x=5
x=(0,5,-4)
The correct option is C....
Answer:
Step-by-step explanation:
The point slope form of a straight line is expressed as
y - y1 = m(x - x1)
Where
m represents slope of the line
y1 represents the initial value of y
x1 represents the initial value of x
If two lines are parallel, it means that they have the same slope. From the equation of the given line, slope = 1/2
Therefore,
m = 1/2
x1 = - 3
y1 = - 2
Substituting into the point slope equation, it becomes
y - - 2 = 1/2(x - - 3)
y + 2 = 1/2(x + 3)
The equation is
y + 2 = 1/2(x + 3)
5 he used 5 hours or however it is out but it’s “5”