Given: y = 2x^2 - 32x + 56
1) y = 2 [ x^2 - 16x] + 56
2) y = 2 [ (x - 8)^2 - 64 ] + 56
3) y = 2 (x - 8)^2 - 128 + 56
4) y = 2 (x - 8)^2 - 72 <----------- answer
Minimum = vertex = (h,k) = (8, - 72)
=> x-ccordinate of the minimum = 8 <-------- answer
Answer:
Step-by-step explanation:
what points do you want me to plot?
Answer:
-11
Step-by-step explanation:
You need to take the absolute value of 12-15 which would be 3. Then take -8-3 which would be -11
Step-by-step explanation:
First solve for y
given equation is 3x-2y ≥ 12
subtract 3x on both sides of the equation which would result with: -2y ≥ 12-3x
divide by -2 on both sides of the equation, flip the sign to ≤ because you are dividing by a negative, then you should get the result y<u> </u><u>≤</u><u> </u>-6 + 3x/2 (should look like a fraction)
y-intercept is at -6
slope is 3/2 (or three halves)
start at -6 on the y-axis, go up 3 across 2 and plot your point, keep repeating when going up and down the graph
Answer:
40th customer
Step-by-step explanation:
Given that there is a promotional event
A sporting good store gave t shirt and free water bottle.
T shirt was given to 8th customer and water bottle to every 10th customer.
For the first person who should get both, he should have number as least common multiple of 8 and 10
8 = 2x2x2
10 = 2x5
Hence least common denominator = 2x2x2x5 = 40
Thus 40th customer will be the first to get both.
