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3 years ago

15

The value of the 3 in the number 731.8

2 answers:

Dominik [7]3 years ago

5 0

Answer:

30

Step-by-step explanation:

the 7 is in the one hundreths place and the 3 is in the tenths place so therefore it is 30. hope this helps :))

Alex777 [14]3 years ago

4 0

Answer:

30

Step-by-step explanation:

Because it is in the tens place

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What is the correct sequence of steps for calculating 9^6 on the scientific calculator?

k0ka [10]

You multiply 9 times nine 6 times. ~9*9*9*9*9*9~

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4 years ago

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What’s the absolute value of 8

Anuta_ua [19.1K]

Answer:

8

Step-by-step explanation:

Absolute value is always the positive value of a number.

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3 years ago

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X/5 + 3 = 9 <br> solve equation

Delicious77 [7]

Answer:

X= 15

Step-by-step explanation:

multiply 5 on x/5 and 9

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3 years ago

lions [1.4K]

Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

This gives:

$Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125$

$Frequency(1) + 103 = 125$

Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

So, the complete table is:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

5 0

3 years ago

Jadyn prepares a bag of candy before a road trip. The bag contains individual pieces of Skittles, M&Ms, Life Savers and Sour

kipiarov [429]

Given condition is- The bag contains individual pieces of Skittles, M&Ms, Life Savers and Sour Patch Kids.

Let the total number of candies in the bag be = x

Then, Skittles are $\frac{1x}{2}$

Candies left = $x-\frac{x}{2}$ = $\frac{x}{2}$

M&Ms are = $\frac{1x}{8}$

Now remaining candies are= $\frac{3x}{8}$

Now Life savers are = $\frac{9x}{32}$

Now adding all these 3 candies

$\frac{x}{2}+ \frac{x}{8}+\frac{9x}{32}$

= $\frac{29x}{32}$

Now the remaining candies sour patch will be =

$x-\frac{29x}{32} =\frac{3x}{32}$

Hence, sour patch kids are $\frac{3}{32}$

3 0

4 years ago