Ask question

Ask question

All categories

3 years ago

7

Assume that y varies inversely with x. If y=8 when x=1.55. Find x when y=-0.62

1 answer:

Lunna [17]3 years ago

3 0

Since xy = a (a is a constant)
a = 8*1.55 = 12.4

so -0.62x = 12.4
-> x= 20

You might be interested in

Find the distance CA

katrin [286]

C' ( 0, 3)

A' ( 2 , 1)

C'A' = CA

C'A' = √(2^2 + 2^2) = √8 = 2√2

C'A' = CA = 2√2

3 0

3 years ago

1.6y+y-4/15y+1 1/6y=2 1/3

Advocard [28]

<u>1.6y+y-4/15y+7/6y=21/3</u>

<u></u>

<u>We move all terms to the left:</u>

<u></u>

<u>1.6y+y-4/15y+7/6y-(21/3)=0</u>

<u></u>

<u></u>

<u>Domain of the equation: 15y!=0</u>

<u></u>

<u>y!=0/15</u>

<u></u>

<u>y!=0</u>

<u></u>

<u>y∈R</u>

<u>Domain of the equation: 6y!=0</u>

<u></u>

<u>y!=0/6</u>

<u></u>

<u>y!=0</u>

<u></u>

<u>y∈R</u>

<u></u>

<u></u>

<u>We add all the numbers together, and all the variables</u>

<u></u>

<u>1.6y+y-4/15y+7/6y-7=0</u>

<u></u>

<u>We add all the numbers together, and all the variables</u>

<u></u>

<u>2.6y-4/15y+7/6y-7=0</u>

<u></u>

<u>We calculate fractions</u>

<u></u>

<u></u>

<u>2.6y+(-24y)/90y^2+105y/90y^2-7=0</u>

<u></u>

<u>We multiply all the terms by the denominator</u>

<u></u>

<u></u>

<u>(2.6y)*90y^2+(-24y)+105y-7*90y^2=0</u>

<u></u>

<u>We add all the numbers together, and all the variables</u>

<u></u>

<u>(+2.6y)*90y^2+(-24y)+105y-7*90y^2=0</u>

<u></u>

<u>We add all the numbers together, and all the variables</u>

<u></u>

<u>105y+(+2.6y)*90y^2+(-24y)-7*90y^2=0</u>

<u></u>

<u>Wy multiply elements</u>

<u></u>

<u>-630y^2+105y+(+2.6y)*90y^2+(-24y)=0</u>

<u></u>

<u>We get rid of parentheses</u>

<u></u>

<u>-630y^2+105y+(+2.6y)*90y^2-24y=0</u>

<u></u>

<u>We add all the numbers together, and all the variables</u>

<u></u>

<u>-630y^2+81y+(+2.6y)*90y^2=0</u>

<u></u>

<u>Hoped this helped :)</u>

5 0

3 years ago

Find the answer x - 3y if x=3,y=-2

GenaCL600 [577]

(3)-(6)
= -3
this is the answer

4 0

3 years ago

Sorry for lack of a better picture, I really really need help please!

Black_prince [1.1K]

B. 6.72the answer is B 6.72

4 0

3 years ago

What are the square roots of 64/144 ?

nordsb [41]

Answer: third option

Step-by-step explanation:

To solve the problem you must apply the proccedure shown below:

- Descompose the numerator and the denominator of the given fraction into its prime numbers:

$64=2*2*2*2*2*2\\144=2*2*2*2*3*3$

Then you can rewrite:

$64=2^6\\144=2^4*3^2$

Then:

$\±\sqrt{\frac{{2^6}}{{2^4*3^2}}}=\±\frac{2^3}{2^2*3}=\±\frac{8}{4*3}=\±\frac{8}{12}$

Therefore, the answer is: $-\frac{8}{12}\ and\ \frac{8}{12}$

4 0

4 years ago

Read 2 more answers