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Stells [14]
3 years ago
6

Pls I Need Help!

Mathematics
1 answer:
Anestetic [448]3 years ago
5 0

Answer: The first one is KL and the second one is most likely FG.

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The volume of a cylinder with a height 3 ft of a and a radius of 4ft
Kobotan [32]
FORMULA : Volume of the cylinder = πr²h


Volume = π x 4² x 3
Volume = π x 16 x 3
Volume = 150.8 ft³
4 0
3 years ago
Add 4x²y,-2xy²,-5xy²,3x²y plz explain​
Vinil7 [7]
4x^2 - 2xy^2
5xy^2 +
3x^2y
_____________
12x^5y^4-2xy^2

This is so because 4+5+3 is 12, then using laws of indices to add your x and y you get x^5 and y^4

To simplify your answer to the lowest you have it in the form of
3x^2y^2(4x^2y - 2xy^2)

If you multiply this as well you get the same answer I got with the addition
3 0
3 years ago
When would you need to use a small standard deviation?
docker41 [41]

Answer:

You can also use standard deviation to compare two sets of data. For example, a weather reporter is analyzing the high temperature forecasted for two different cities. A low standard deviation would show a reliable weather forecast.

Step-by-step explanation:

4 0
3 years ago
Some transportation experts claim that it is the variability of speeds, rather than the level of speeds, that is a critical fact
scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

<em>H</em>₀: The variance of speeds does not exceeds 75 (mph)², i.e. <em>σ</em>² ≤ 75.

<em>Hₐ</em>: The variance of speeds exceeds 75 (mph)², i.e. <em>σ</em>² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, <em>α</em> = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}

    =\frac{(55-1)\times 94.7}{75}\\\\=68.184

The test statistic value is, 68.184.

Decision:

cal.\chi^{2}=68.184

The null hypothesis will not be rejected at 5% level of significance.

Conclusion:

The variance of speeds does not exceeds 75 (mph)². Thus, concluding that driving conditions are not dangerous on this highway.

7 0
3 years ago
ms adams shares out 40 pencils between niamh and jack in the ratio 3:5 how many pencils does each child get
Neporo4naja [7]
40 times 3/3+5= Niamh’s amount = 40x3/8 = 15 pencils
40 times 5/3+5= Jack’s amount =
40x5/8 = 25 pencils
5 0
3 years ago
Read 2 more answers
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