To solve this, we need to use the z statistic. The formula for z score is:
z = (x – u) / s
where x is sample value = less than 90, u is the sample mean = 90.6, s is the standard deviation = 17.2
z = (90 – 90.6) / 17.2
z = -0.035
From the standard distribution tables:
P (z = -0.035) = 0.4860
Therefore there is about 48.60 % chance that it will be less than 90 pounds
Answer: the last option (:
Step-by-step explanation:
You always put the slope in front of the x intercept in the equation.
What language are you writing this in? C? Javascript? Java? Are you allow to have parameters?
The general idea should be the same. Since 1 dollar = 100 pennies, we should write something like...
Java:
public static double numberofpennies(double dollars, double penny) {
double sum = 0;
// The amount of pennies that dollar represents
double converted = dollars * 100.0;
sum = converted + penny;
return sum;
}
Note: You should probably place this question under the category computer and technology instead of math. Also, this is just an example of what you could possibly write. What parameters you are allowed to use, what type (double? int? etc?) of pennies are you allowed to return, etc. depends on how you write it.
Answer:
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Answer:
the inflection points are
So,
It is concave down at the intervals
![(-\infty , -0.85] \cup [-0.14,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%20%2C%20-0.85%5D%20%5Ccup%20%5B-0.14%2C%5Cinfty%29)
And it would be concave up at
Step-by-step explanation:
Remember that to find inflection points you need to find where
Since
Then using the product and the chain rule you have that
And then, using again the chain rule and the product rule you have that
Therefore you have to solve the equation
Using the quadratic equation you get that there are two solutions, so the inflection points are
So,
Now remember that a function is concave up if the derivative is greater than zero and concave down if the derivative is less than zero. Therefor you have to solve these inequalties
And you would get that is concave down at the intervals
And it would be concave up at
