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3 years ago

HELP!!

Mathematics

1 answer:

Naily [24]3 years ago

3 0

24 cm bc 25 squared is 625 and 7 squared is 49. 625-49=576. Now the square root of 576 is 24 and boom your answer

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Does the following represent a Direct or Indirect variation? y = 5 Direct Indirect

Nataly_w [17]

Answer:

Yes, y=5x is a direct variation and the constant of variation is 5 .

7 0

3 years ago

Read 2 more answers

1 a.) 20cm^2 to mm^2

mixas84 [53]

Answer:

a) 200 mm^2

b) 500 mm^2

c) 3.75e + 8

d) 6390 cm^2

e) 650 cm^2

f) 20 m/s

Step-by-step explanation:

For a) and b): 1 cm = 10 mm, multiply 20 (and 50) by 10

For c): the formula is to multiply 1e + 8

For d): 1 Liter = 1000 Cubic Centimeters (hopefully that's what you're referring to)

For e): 10 mm = 1 cm, divide by 10

For f): divide the value by 3.6

6 0

3 years ago

Yanika is teaching a swim class. She needs to divide the class into teams for a relay race. There is 18 students.

coldgirl [10]

A possible sizes two teams of 9 or 9 teams of 2, 6 teams of 3 or 3 teams of 6

B yes 3 lanes could divide her 18 students by putting 6 people in each lane
18/3= 6

8 0

3 years ago

The quantity demanded x each month of Russo Espresso Makers is 250 when the unit price p is $138. The quantity demanded each mon

Stells [14]

Answer:

(a) $D(q)=\frac{-1}{25} q+148$

(b) $S(q)=\frac{1}{50}q+58$

Step-by-step explanation:

(a) For the demand equation D(q) we have

P1: 138 Q1: 250

P2: 108 Q2: 1000

We can find m, which is the slope of the demand equation,

$m=\frac{p_{2} -p_{1} }{q_{2} -q_{1} }=\frac{108-38}{1000-250} =\frac{-30}{750}=\frac{-1}{25}$

and then we find b, which is the point where the curve intersects the y axis.

We can do it by plugging one point and the slope into the line equation form:

$y=mx+b\\\\D(q)=mq+b\\\\138=\frac{-1}{25}(250) +b\\\\138=-10+b\\\\138+10=b=148$

With b: 148 and m: -1/25 we can write our demand equation D(q)

$D(q)=\frac{-1}{25} q+148$

(b) to find the supply equation S(q) we have

P1: 102 Q1: 2200

P2: 102 Q2: 700

Similarly we find m, and b

$m=\frac{p_{2} -p_{1} }{q_{2} -q_{1} }=\frac{72-102}{700-2200} =\frac{-30}{-1500}=\frac{1}{50}$

$y=mx+b\\\\D(q)=mq+b\\\\72=\frac{1}{50}(700) +b\\\\72=14+b\\\\72-14=b=58\\$

And we can write our Supply equation S(q):

$S(q)=\frac{1}{50}q+58$

(c) Now we may find the equilibrium quantity q* and the equilibrium price p* by writing D(q)=S(q), which means the demand equals the supply in equilibrium:

$D(q)=S(q)\\\\\frac{-1}{25}q+148=\frac{1}{50}q+58\\\\$