Answer:
The value of Car B will become greater than the value of car A during the fifth year.
Step-by-step explanation:
Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.
In the attached excel file, the following are used:
Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000
Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000
Annual Depreciation expense of Car B in Year 7 = Beginning value of Car B in Year 7 = 2,000
Conclusion
Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.
The answer would be 40
5 divided by 1/8
5/1 divided by 1/8
5/1 divided by 8/1
then you would multiply
5 times 8
=40/1 or 40
The effect on the photos perimeter and area would be that the resulting photo would be larger than intended.
Answer:
from the top down
y=7
y=4
y=3
y=4
y=7
Step-by-step explanation:
y=(-2)²+3
y=4+3
y=7
y=(-1)²+3
y=1+3
y=4
y=0²+3
y=0+3
y=3
y=1²+3
y=1+3
y=4
y=2²+3
y=4+3
y=7
hope this helps :)
23 or 23/1 or 23.0
Hope this helps ;)
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