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3 years ago

There are more inches on a football field (100 yards) than there are centimeters on a 28 meter basketball court. True or false?

Mathematics

1 answer:

romanna [79]3 years ago

5 0

Answer:

true

Step-by-step explanation:

on a football feild there are 4,320 inches and on a basketball court there are 2,865 centemeters

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Seventy homes that were for sale in Tampa, Florida in Spring of 2019 were randomly selected. A regression model to predict house

Art [367]

Answer:

d. The slope of the relationship between firstfloorsquarefootage and price is moresteep for homes near the beach than elsewhere in Tampa.

Step-by-step explanation:

In this regression model, we have a positive slope. This positive slope is indicative of an increase. So to interpret this slope, we would say that the slope of the relationship that exists between the two variables (price and firstfloorsquarefootage) is steeper for the homes that are closer to the beach compared to the ones that are elsewhere. Therefore option D is our answer.

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2 years ago

I am ust typing this so it will let me post this But Please Help

andre [41]

Answer:

${4}^{3} = 64$

Step-by-step explanation:

$\frac{ {4}^{8} }{ {4}^{5} } = {4}^{3}$

Subtract the numerator exponent from the denominator exponent.

$8 - 5$

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2 years ago

I need help with my algebra.

Natasha_Volkova [10]

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6 0

2 years ago

Read 2 more answers

Use the figure below. What is m

tankabanditka [31]

Answer:

150

Step-by-step explanation:

90-60 is 30

180-30 is150

3 0

2 years ago

Backgammon is a board game for two players in which the playing pieces are moved according to the roll of two dice. players win

Ivahew [28]

The rolls of the dice are independent, i.e. the outcome of the second die doesn't depend in any way on the outcome of the first die.

In cases like this, the probability of two events happening one after the other is the multiplication of the probabilities of the two events.

So, the probability of rolling two 6s is the multiplication of the probabilities of rolling a six with the first die, and another six with the second:

$P(\text{rolling two 6s}) = P(\text{rolling a 6}) \cdot P(\text{rolling a 6}) = \dfrac{1}{6} \cdot \dfrac{1}{6} = \dfrac{1}{36}$

Similarly,

$P(\text{rolling two 3s}) = P(\text{rolling a 3}) \cdot P(\text{rolling a 3}) = \dfrac{1}{6} \cdot \dfrac{1}{6} = \dfrac{1}{36}$

Actually, you can see that the probability of rolling any ordered couple is always 1/36, since the probability of rolling any number on both dice is 1/6:

$P(\text{rolling any ordered couple}) = P(\text{rolling the first number}) \cdot P(\text{rolling the second number}) = \dfrac{1}{6} \cdot \dfrac{1}{6} = \dfrac{1}{36}$

7 0

2 years ago