Just put 3.150 lol that what I did
Answer:
1. x = 21
2. m∡ABC = 51°
Step-by-step explanation:
First problem, solve for x
the sum of inside angles of a triangle is 180
also the supplementary angle for L = 180 - 100 is 80°
now you can add all angles
80 + 2x - 11 + 2x + 27 = 180
4x + 96 = 180
4x = 84
x = 21
Second problem, solve for m∡ABC
the sum of inside angles of a triangle is 180
also the supplementary angle for C = 180 - 148 is 32°
now you can add all angles
31 + 2x - 15 + x - 5 = 180
3x + 12 = 180
3x = 168
x= 56,
now solve for m∡ABC = (x - 5)° = (56 - 5)° = 51°
Answer:
(3, 0).
Step-by-step explanation:
dentifying the vertices of the feasible region. Graphing is often a good way to do it, or you can solve the equations pairwise to identify the x- and y-values that are at the limits of the region.
In the attached graph, the solution spaces of the last two constraints are shown in red and blue, and their overlap is shown in purple. Hence the vertices of the feasible region are the vertices of the purple area: (0, 0), (0, 1), (1.5, 1.5), and (3, 0).
The signs of the variables in the contraint function (+ for x, - for y) tell you that to maximize C, you want to make y as small as possible, while making x as large as possible at the same time.
Hence, The Answer is ( 3, 0)
Answer:
a. y^ -1 = e^x +2
Step-by-step explanation:
y = ln (x-2)
Exchange x and y
x = ln (y-2)
Solve for y
Raise each side with a base of e
e^ x = e^(ln(y-2)
e^x = y-2
Add 2 to each side
e^x +2 =y