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KengaRu [80]
3 years ago
7

*I WILL MARK U BRAINLIEST IF IT CORRECT* Using the following set of data, calculate the lower quartile, the upper quartile, and

the interquartile range.
20, 22, 25, 28, 29, 30, 32, 33, 34

Be sure to show your work for finding:

the lower quartile
the upper quartile
the interquartile range
Mathematics
1 answer:
SSSSS [86.1K]3 years ago
4 0

Answer:

1. 20

2. 34

3. 14

Step-by-step explanation:

20 is smallest number

34 is biggest number

34-20=14

range is 34-20

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Jerome solves the inequality y–2 ⩽ 9 in one step, writing y ⩽ 11 as the solution. What property best justifies the step he used
DedPeter [7]
The answer is b because he added 2
8 0
3 years ago
30 POINTS FOR THE GENUIS WHO CAN ANSWER THIS!!
bearhunter [10]

Answer:

Answers are below in bold

Step-by-step explanation:

1) A = 1/2bh          Use this equation to find the area of each triangular base

A = 1/2(8)(6)         Multiply

A = 1/2(48)           Multiply

A = 12cm²           Area of each triangular base

2) A = L x W        Use this equation to find the area of the bottom rectangular face

A = 20 x 8          Multiply

A = 160 cm²       Area of the bottom rectangular face

3) A = L x W        Use this equation to find the area of the back rectangular face

A = 20 x 6          Multiply

A = 120 cm²       Area of the back rectangular face

4) A = L x W        Use this equation to find the area of the sloped rectangular face

A = 20 x 10         Multiply

A = 200 cm²      Area of the sloped rectangular face

5) To find the total surface area of the triangular prism, add together all of the numbers.

A = 12 + 12 + 160 + 120 + 200       Add

A = 504 cm²       Total area of the triangular prism

6 0
3 years ago
2. A solar lease customer built up an excess of 6,500 kilowatt hours (kwh) during the summer using his solar
tia_tia [17]

9514 1404 393

Answer:

  a)  E = 6500 -50d

  b)  5000 kWh

  c)  the excess will last only 130 days, not enough for 5 months

Step-by-step explanation:

<u>Given</u>:

  starting excess (E): 6500 kWh

  usage: 50 kWh/day (d)

<u>Find</u>:

  a) E(d)

  b) E(30)

  c) E(150)

<u>Solution</u>:

a) The exces is linearly decreasing with the number of days, so we have ...

  E(d) = 6500 -50d

__

b) After 30 days, the excess remaining is ...

  E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days

__

c) After 150 days, the excess remaining would be ...

  E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system

The supply is not enough to last for 5 months.

3 0
2 years ago
2(3x – 1) = –6x – 2 can someone help
Gnom [1K]

Let's solve your equation step-by-step.

2(3x−1)=−6x−2

Step 1: Simplify both sides of the equation.

2(3x−1)=−6x−2

(2)(3x)+(2)(−1)=−6x+−2(Distribute)

6x+−2=−6x+−2

6x−2=−6x−2

Step 2: Add 6x to both sides.

6x−2+6x=−6x−2+6x

12x−2=−2

Step 3: Add 2 to both sides.

12x−2+2=−2+2

12x=0

Step 4: Divide both sides by 12.

12x/12= 0/12

x=0

Answer:

x=0

HOPE THIS HELPS!!! :)

5 0
3 years ago
A 10 sided die is numbered 1-10 if you roll it 60 times what is the best prediction for how many times you would eithrr a 1 or 2
Kamila [148]

Answer: 12

Step-by-step explanation:

So if its 1-10, and you can either roll a 1 or 2, it would be 2/10, then simplified to 1/5, and in order to get the answer you need to multiply it by 60

1/5 x 60/1 = 12

(sorry if I got it wrong, feel free to correct me if I did)

8 0
2 years ago
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